ksPeopleTabWindowHelp82%Mon 1:Vind Tap - Cengage Learnirgi/evo/index.html?deploymentld%3D55750828934189288909969212&elSBN=9781305657571&nbld%3D2199.KMINDTAPQ Search this coursUse the References to access important values if needed for this question.Write ground-state electron configurations for the ions Be", P, Ca2*and Fe*. Which do you expect will be paramagnetic due to thepresence of unpaired electrons?(Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2sor in condensed form as [He]2s '.)ionelectron configuration paramagneticBe*p3-Ca2+Fe2+

We know that the ground state electronic configuration of the corresponding neutral element as…

Write ground-state electron configurations for the ions Be", P, Ca2*and Fe2*. Which do you expect will be paramagnetic due to the presence of unpaired electrons? (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s or in condensed form as [He]2s '.) 1 ion electron configuration paramagnetic Bet p3- Ca2+ Fe2+

Write ground-state electron configurations for the ions Be", P, Ca2and Fe2. Which do you expect will be paramagnetic due to the presence of unpaired electrons? (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s or in condensed form as [He]2s '.) 1 ion electron configuration paramagnetic Bet p3- Ca2+ Fe2+

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
( plz do all with explanation
Ee.5. With explanation please....
4. Ksp=4.1x10-36 for Pb3(AsO4)2Calculate Eofor Pb3(AsO4)2(s) + 6e-  3Pb(s) + 2AsO43-Pb2+ +2e-  Pb(s) Eo= -0.126 V
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/gen_chem/eo.html ^ table image:
Calculate the Constant Weight (in grams) of the Empty Crucibles. Show your solution. Crucible No. 1 2 3 Weighing 1 22.6035 22.0223 24.1535 Weighing 2 22.6017 22.0204 24.1533 Weighing 3 22.5994 22.0199 - Weighing 4 22.5992 - - Constant Weight, g ??? ??? ???
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
What could be the assumption when the MW of the sample does not match calculated molecualr weight from ∆Tb = mKb despite carefull data processing? The sample is not the compound of interest There are some impurities that affeced the boiling temperature Low heat is used to achieve boiling condition none of the assumption is valid 1 and III are valid assumptions all are valid assumptions I and II are valid assumptions
Aleks data for AgBrO3 is 5.38 x 10^-5