Write the vector expression for the acceleration a of the mass center G of the simple pendulum in both n-t and x-y coordinates for the instant when 0 = 54° if = 2.06 rad/sec and 0 = 4.395 rad/sec². Answers: a = (i a=(i 2.7' + it i M e) ft/sec² j) ft/sec² 3

Write the vector expression for the acceleration a of the mass center G of the simple pendulum in both n-t and x-y coordinates for the instant when 0 = 54° if = 2.06 rad/sec and 0 = 4.395 rad/sec². Answers: a = (i a=(i 2.7' + it i M e) ft/sec² j) ft/sec² 3

Name: Write the vector expression for the acceleration a of the mass center
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Description: Write the vector expression for the acceleration a of the mass center G of the simple pendulum in both n-t and x-y coordinates for theinstant when 0 = 54° if 0 = 2.06 rad/sec and 0= 4.395 rad/sec².Answers:a = (ia = ( i2.7'Ci+ iMee) ft/sec²j) ft/sec²

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 29P: The angular position of a pendulum is represented by the equation = 0.032 0 cos t, where is in...

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