Write two java methods 1)static void insertionSort(T[] array, Comparator cc){} This should run in O(n^2) time in the worst case. 2)static void mergeSort(T[] array, Comparator cc){} This should run in O(nlogn) time in the worst case. Remember that the Comparator interface in Java defines how we can compare objects of type T. The interface expects the existence of a method: int compare(T o1, T o2) which compares o1 and o2 for order. More specifically: if o1 < o2, then compare returns a negative value; if o1 == o2, then compare returns 0 (this should be consistent with .equals); if o1 > o2, then compare returns a positive value.
Write two java methods 1)static void insertionSort(T[] array, Comparator cc){} This should run in O(n^2) time in the worst case. 2)static void mergeSort(T[] array, Comparator cc){} This should run in O(nlogn) time in the worst case. Remember that the Comparator interface in Java defines how we can compare objects of type T. The interface expects the existence of a method: int compare(T o1, T o2) which compares o1 and o2 for order. More specifically: if o1 < o2, then compare returns a negative value; if o1 == o2, then compare returns 0 (this should be consistent with .equals); if o1 > o2, then compare returns a positive value.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Write two java methods
1)static <T> void insertionSort(T[] array, Comparator<T> cc){}
- This should run in O(n^2) time in the worst case.
2)static <T> void mergeSort(T[] array, Comparator<T> cc){}
- This should run in O(nlogn) time in the worst case.
Remember that the Comparator<T> interface in Java defines how we can compare objects of type T. The interface expects the existence of a method:
int compare(T o1, T o2)
which compares o1 and o2 for order. More specifically:
-
- if o1 < o2, then compare returns a negative value;
- if o1 == o2, then compare returns 0 (this should be consistent with .equals);
- if o1 > o2, then compare returns a positive value.
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