Java 1. Implement ArrayUnorderedList class which will extend ArrayList by defining the following additional methods (i) public void addToFront(T element); //Adds the specified element to the front of the list. (ii) public void addToRear(T element); //Adds the specified element to the rear of the list. (iii) public void addAfter(T element, T target); //Adds the specified element after the specified target element. a. Create an object of ArrayUnorderedList class and perform some add, remove, and search operations and finally print the entire Stack.
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Java
1. Implement ArrayUnorderedList<T> class which will extend ArrayList<T> by defining the following additional methods
(i) public void addToFront(T element); //Adds the specified element to the front of the list.
(ii) public void addToRear(T element); //Adds the specified element to the rear of the list.
(iii) public void addAfter(T element, T target); //Adds the specified element after the specified target element.
a. Create an object of ArrayUnorderedList<T> class and perform some add, remove, and search operations and finally print the entire Stack.
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- In java, Implement a method that removes all duplicates. Keep the first instance of the element but remove all subsequent duplicate elements.public void removeDuplicates() see the picture for the right output. Given files: Demo6.java public class Demo6 { public static void main(String[] args) { MyLinkedList<String> list = new MyLinkedList<>(); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); for (int x = 0; x < list.size(); x += 1 + x/3) { System.out.println("Removing element at index: " + x); list.remove(x); } System.out.println("Result"); System.out.println(list); System.out.println("Shuffling"); list.shuffle(7777); System.out.println(list); System.out.println("Removing duplicates (keeping first instance)"); list.removeDuplicates(); System.out.println(list); }} TestBench.java import java.util.AbstractList; public class TestBench { public static…In java A supermarket wants to reward its best customer of each day, showing the customer’s name on a screen in the supermarket. For that purpose, the store keeps an ArrayList.Create a class customer having id, name, gender, and bill provide appropriate getters/setters and constructors also provide toString method.In the Store class, make an ArrayList of customers, store name, and address implement methods public void addSale(Customer c) that will add customers to the arraylist.public void RemoveCustomer(int id);public void UpdateCustomerRecord(int Id);public displayAll();public String nameOfBestCustomer() to record the sale and return the name of the customer with the largest sale. public ArrayList nameOfBestCustomers(int topN) so that it displays the top customers, that is, the topN customers with the largest sales, where topN is a value that the user of the program supplies. Write a program that prompts following menu and ============================================…import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…
- Add a void instance method replaceAll(E oldE, E newE) in the MyLinkedList class to replace the occurrence of all oldE value with the specified newE value. Implement this method in O(n) time. import java.util.*; public class PExamCh24 { public static void main(String[] args) { new PExamCh24();}public PExamCh24() { // Create a list for strings MyLinkedList<String> list = new MyLinkedList<>(); // Add elements to the list list.add("America"); // Add America to the list System.out.println("(1) " + list); list.add(0, "Japan"); // Add Canada to the beginning of the list System.out.println("(2) " + list); list.add("Russia"); // Add Russia to the end of the list System.out.println("(3) " + list); list.addLast("Japan"); // Add France to the end of the list System.out.println("(4) " + list); list.add(2, "Japan"); // Add Germany to the list at index 2 System.out.println("(5) " + list); list.add(5, "Norway"); // Add Norway to the list…Java 1. Implement a List using array: a. Implement ArrayList<T> class of ListADT<T> interface which will define the following methods (i) public T removeLast(); //Removes and returns the last element in the list. (ii) public T removeFirst(); //Removes and returns the first element in the list. (iii) public T remove(T element); //Removes and returns the specified element. (iv) public boolean contains(T target); //Return True if the list contains the target element otherwise False. (v) public String toString(); // Returns a string representation of the list. b. Implement ArrayUnorderedList<T> class which will extends ArrayList<T> by defining the following additional methods (i) public void addToFront(T element); //Adds the specified element to the front of the list. (ii) public void addToRear(T element); //Adds the specified element to the rear of the list. (iii) public void addAfter(T element, T target); //Adds the specified element after the specified target…Write a Java class myLinkedList to simulate a singly linked list using arrays as the underlying structure. Include the following methods: 1. insert an element within the linked list.(this should also work for the front and the rear of the list) 2. Remove an element from the linked list 3. Display (print) the elements of the linked list in order. 4. A method to check if the list is "empty". Test your solution using a linked list that initially has the characters A, B, D, E, F, and G. Insert "C" between B and D. Remove element "F". [Hint: One solution (recommended) is to use 2 arrays. One for the data, and the other for the "next" pointer. Also, consider using dummy nodes for the front, and possibly the rear of the list] Extend the solution so that it simulates a doubly linked list! (hint: You will need a third array to represent the "backward" pointers)
- in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…Import the ArrayList and List classes from the java.util package to create a list of phone numbers and also import the HashSet and Set classes from the java.util package to create a set of unique prefixes. Create a class called PhoneNumberPrefix with a main method that will contain the code to find the unique prefixes. Create a List called phoneNumbers and use the add method to add several phone numbers to the list. List<String> phoneNumbers = new ArrayList<>(); phoneNumbers.add("555-555-1234"); phoneNumbers.add("555-555-2345"); phoneNumbers.add("555-555-3456"); phoneNumbers.add("444-444-1234"); phoneNumbers.add("333-333-1234"); Create a Set called prefixes and use a for-each loop to iterate over the phoneNumbers list. For each phone number, we use the substring method to extract the first 7 characters, which represent the prefix, and add it to the prefixes set using the add method. Finally, use the println method to print the prefixes set, which will contain all of…Fix the following method printEvenIndex so that it will print out the Integers at even indices of the passed-in ArrayList list. import java.util.*; public class Test1 { public static void printEvenIndex(ArrayList<Integer> list) { for (int i) { if (i % 2 == 1) { System.out.print(list.get(i) + ", "); } } } public static void main(String[] args) { //instantiate ArrayList and fill with Integers ArrayList<Integer> values = new ArrayList<Integer>(); int[] nums = {1, 5, 7, 9, -2, 3, 2}; for (int i = 0; i < nums.length; i ++) { values.add(nums[i]); } System.out.println("Expected Result:\t 1, 7, -2, 2,"); System.out.print("Your Result:\t\t "); printEvenIndex(values); } }
- Java - Given a list (44, 80, 96, 33, 15, 42, 73, 99, 91, 77) and a gap array of (5, 4, 1):Design and implement a getLastHalf() method for the MyLinkedList class. The method should return the last half of the list as a new list leaving the original list intact. If the list has an uneven number of elements the extra one element must be in the list returned. Example : [1,3,5,4] return [5,4] and [1,6,9] return [6,9]. Follow the three step method for designing the method Develop the java code for the method Create a test program to test the method thoroughly using the Integer wrapper class.Design and implement a getLastHalf() method for the MyLinkedList class. The method should return the last half of the list as a new list leaving the original list intact. If the list has an uneven number of elements the extra one element must be in the list returned. Example : [1,3,5,4] return [5,4] and [1,6,9] return [6,9]. Follow the three step method for designing the method Develop the java code for the method Create a test program to test the method thoroughly using the Integer wrapper class. public class MyLinkedList<E> { private Node<E> head, tail; public MyLinkedList() { head = null; tail = null; } /** Return the head element in the list */ public E getFirst() { if (head == null) { return null; } else { return head.element; } } /** Return the last element in the list */ public E getLast() { if (head==null) { return null; } else { return tail.element; } } /** Add an element to the beginning of the list */ public void prepend(E e) { Node<E> newNode = new…