Question
Asked Feb 5, 2019
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Draw an impedance diagram for the electric power system shown in the figure attached, showing all impedances in per unit on a 100-MVA base. Choose 20kV as the voltage base for generator. The three-phase power and line-line ratings are given in the figure attached.

X = 9%
X-16%
X=20%
X = 9%
X=120 Ω
S 48 MW +j64 Mvar
1 90 MVA 20 kV
80 MVA
20/200kV
T2: 80 MVA 200 20 kV
G90 MVA 18 kV
Line:
Load
200 kV
200 kV
Τι
T2
Line
Load
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X = 9% X-16% X=20% X = 9% X=120 Ω S 48 MW +j64 Mvar 1 90 MVA 20 kV 80 MVA 20/200kV T2: 80 MVA 200 20 kV G90 MVA 18 kV Line: Load 200 kV 200 kV Τι T2 Line Load

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Expert Answer

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Step 1

We can obtain the impedance diagram by using below steps: -

The base voltage VBG1 on the LV side of T1 is 20 kV. Hence the base on its HV side is: -VB1 = 20 (200/20) = 200 kV

This fixes the base on the HV side of T2 at VB2 = 200 kV, and on its LV side atVBG2 = 200(20/200) = 20 kV

Step 2

The generator and transformer reactances in per unit on a 100 MVA base, as below: -

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Step 3

The base impedance for the transmission line is

ZBL = (200)2/100 = 400 ohms

The per unit line reactance is

Line:    X = (120/400) = 0.30 per unit

The load impedance in ohms is:

ZL = (VL-L)2/(S*L(3-phase) = (200)2/(48-j6...

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Electrical Engineering

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