x2 + z2 = 7 Write an equation for the cross section at  y = −7 using x and z. Write an equation for the cross section at  y = 7  using x and z.

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Q: Q6. Find the general solution using variation of parameters of y" + 4y = 8tant

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Q: 2. Solve the equation using Variation of Parameters: y" – 5y' + 4y = x .

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A: Solution is given as below:

Q: Solve for y in terms of x. 16x+4/3y=15 Y= What is step by step procedure to solve.

A: Solve for y in terms of x. 16x+4/3y=15 Y= What is the step by step procedure to solve?

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Q: Y varies directly with x , and Y=3 when X=2. Find Y when X= 7

A: We can find the answer as below

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A: Solution :-

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A: Solution :-

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Q: Q2\Using the variation of parameter , find the solution of: y'+9y= sec3x

A: Particular solution by variation of parameter where W is wronskian of y1 and y2.

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Q: Select the equations that show a proportional relationship between x and y. y = 10x y = 8x - 1

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Q: How to solve this equation y" - 4y" + 2y' - 16y = 4x + 1 using Variation of Parameters.

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Q: Find the general solution of the equation by the variation of parameters method: y" – 2y'+ y = x?e"…

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