-x+3y=-15 x+4y=-13

Q: y"+y' - 2y = x2

A: Solution :-

Q: y' = y2 - 4

A:

Q: y" - 4y' = 0

A: Given: Ordinary equation is  y''-4y'=0

Q: y" - y' - 2y = 0

A: Given the differential equation is y" - y' - 2y = 0 Here the auxiliary equation is m2 - m - 2 = 0

Q: y" + 5y' - 4y = 0

A: SOLUTION-

Q: y" - 4y' + 5y = 0

A:

Q: 1) y" - 36y = 0.

A:

Q: -3(2y-8)-y = 3(y-3)

A: We open the brackets and simplify the equations of both the sides( Left hand side and right hand…

Q: -5(6y-5)-y=-3(y-3)

A: First of all, to solve the given equation and find the value of y, remove the parentheses.

Q: Find y 2 x - 3y =7

A: The given equation is 2x3-3y2=7 To find: y''

Q: -1 -2s [s²

A:

Q: (b) -+3r- 6|+ 2, where r > 2

A:

Q: -4x + 3y = 17 3× -2yニ-12

A: Solving the system of linear equations

Q: y = () Зx2-2 х+3

A: I am using the chain rule to find the first order derivative of the given equation

Q: y"-2y'-8y = 0 if y(0) = 3; y'(0) = 6

A:

Q: - 2 y+1 z-4 = 4 2 -2

A:

Q: -X – y = 5

A: The equation is -x - y = 5

Q: y" – 6y + 10 y = 50 x + 3e - +20

A: We are asked to solve the differential equations.

Q: - y" - 5y + 4y= 2et

A: y'' -5y' +4y=2etThe general solution to axy''+bxy'+cxy=gx can be written asy=yh+ypyh is the solution…

Q: -6|5-2y|=-9

A: Solve equations,

Q: 1. y-14y-48y 0

A:

Q: Evaluate -2xy + 5y2 for x = -3 and y = 4.

A: Consider the given: Let the given polynomial be px,y,px,y=−2xy+5y2 Substitute the given values of x…

Q: (y>-- (2x-y 2-3 AALAM

A: Here we have to graph the given inequality:-  y>-x2-22x-y ≥-3

Q: =2 at (-1.-1) y 3.

A:

Q: Then P(-3 < X < 3|Y = 2) =

A:

Q: -5y-3(-7y-2)=3-5(7-y)

A: We have to solve the equation -5y-3(-7y-2)=3-5(7-y)

Q: X2-x-4=0

A: Given,

Q: -4+3

A:

Q: -2x - y =12  9x+y = -26

A: The given equations are -2x - y =12     ....... (1) 9x+y = -26    ........ (2)

Q: y = x² - 4

A: as per guideline i can solve only first question

Q: y2x-4 +ys2

A:

Q: y=2(x - 1)2 + 3

A: Given, To graph y=2(x-1)2+3

Q: y= ( х-6 3 1. у %3 Зx+4,

A: As per our guideline we are supposed to be answer only one question you can repost other questions…

Q: - 10y + 25y-0; y (0)-9 y(1)-0

A:

Q: If y=3 then -y2=

A: Given Here the objective is to find the value of M

Q: Find A" for A -3 -27 :) A- [ 2) A 5 9 3 4-

A: To find A-1

Q: 3y² + 5y - 8

A: The given quadratic equation is:  3y2+5y-8

Q: y = x - 10x - 5

A:

Q: (-x³y?)®

A: (-x5y7)6

Q: x2-3x-40=0

A: We have to factor -40 so that sum of the factors =-3-40=-8 times 5 And -8+5=-3So we will write…

Q: X - 11-1+y 入(o8 ~

A: x= 11.1+y   .....1 x(0.8) =y     ......2

Q: -3-X, -3y, -3z]

A: We have to find div(V) from the given

Q: (x³y-³)²

A: Given :

Q: 4x-3y=14 4x+y=22

A: Given   4x-3y=14 4x+y=22 Solve by eliminating one variable and find value of other then use that in…

Q: y" + 2y' - y = 0

A: Definition used -         The solution of the linear differential equation -         The…

Q: x- 4y = -10 x+y = 5

A: Given, x-4y=-10         ----(i) x+y=5            ----(ii)