You are given an empty hash table of size 7 that uses open addressing. The Q4) following sequence of keys is to be inserted: 25 77 0 23 3 15 Insert these keys using each of the following approaches. If overflow occurs, say so, and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 2 3 2.

You are given an empty hash table of size 7 that uses open addressing. The Q4) following sequence of keys is to be inserted: 25 77 0 23 3 15 Insert these keys using each of the following approaches. If overflow occurs, say so, and indicate the element that causes the overflow. a. h(x) = x % 7; linear probing b. h(x) = x % 7; quadratic probing 1 2 3 2.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please convert to C language //linear probing#include <bits/stdc++.h>using namespace std; void add_using_linear_probing(int hash[], int a){ //hash function h(x)=x%10 int k = a % 10; //linear probing while (true) { if (hash[k] == -1) { hash[k] = a; break; } k = (k + 1) % 10; //linear increment of probe }} int main(){ //set of input numbers vector<int> arr{ 123, 124, 333, 4679, 983 }; //initialize the hash table //each entry of the hash table is a single entry int hash[10]; //size of hashtable is 10 memset(hash, -1, sizeof(hash)); //initialize with empty initially for (int a : arr) { //hashing add_using_linear_probing(hash, a); } cout << "---------using linear probing---------\n"; cout << "Hash table is:\n"; for (int i = 0; i < 10; i++) { if (hash[i] == -1) cout << i << "->" << "Empty" <<…
Assume an open addressing hash table implementation, where the size of the array is N = 19, and that double hashing is performed for collision handling. The second hash function is defined as: d(k) = q -k mod q, where k is the key being inserted in the table and the prime number q is = 7. Use simple modular operation (k mod N) for the first hash function. i) Show the content of the table after performing the following operations, in order:put(45), put(25), put(12), put(61), put(38), put(88), remove(12), put(39), remove(61), put(18), put(29), put(29), put(35).i) What is the size of the longest cluster caused by the above insertions? ii) What is the number of occurred collisions as a result of the above operations? iii) What is the current value of the table’s load factor?
2. Implement the hash table for the following elements: a. 22,32,45,67,89,9 Use Double hashing technique to handle the collision. [ hash1(key)=key%10, hash2(key)=PRIME- (key%PRIME) ].
20 a) Given a hashing function hash(x) = ((x * x) + x) % 11, Insert the value 17 into each hash table using the rules specified below. Note that some of the boxes in each hash table are already full. If there’s a collision, start the probing at i = 0 and increment from there if you collide. b) After we insert our new data (that 17) into these hash tables, should we resize and rehash the values? Why or Why not? c) If this was a hash table using separate chaining instead of linear probing, would it be time to rehash after we insert 17?
1) Suppose hashing is being done by using open addressing with linear probing. The hash function tobe used for an element with key k is h(k) = k mod 11. Show the contents of the hash table afterinserting the following keys in order into the hash table:27 40 22 15 31 18 36 19 20
use python code. Below is the code for parallel list implementation of dictionary ADT. Modify the code below tohandle collision using double hashing technique. Use the following hash functions:h(k) = k mod n, where is the number of slots in the hash tableh’(k) = 7 - (k mod 7)and handles collisions by placing an item in the first available cell of the seriesA[(i + f(j)) mod N] for j = 1, 2, 3, ..., where f(j) = j*h’(k). import osclass Dictionary:def __init__(self, size):self.keys = [None] * sizeself.values = [None] * sizeself.n = 0self.size = sizedef __str__(self):keys_str = "{"if not self.empty():for i in range(0, self.size - 1):keys_str += "({},{}),".format(self.keys[i], self.values[i])keys_str += "({},{})".format(self.keys[self.size - 1], self.values[self.size - 1])return keys_str + "}"def empty(self):return self.n == 0def dictionary_size(self):return self.ndef hash(self, key):return key % self.size def insert_item(self, key, item):if self.n == self.size:print("Dictionary…
Outline the steps in inserting a data M into a hash table. Assume that the collisionresolution technique used is double hashing.
#include <stdio.h>#include <stdlib.h>#include <string.h>#define capacity 101 // Size of Hash Table int hash_function(char* str) { int i = 0; for (int j=0; str[j]; j++) i += str[j]; return i % capacity;} struct Ht_item { char* name; int numberCourses;}; // Hash Table Definitionstruct HashTable { struct Ht_item** items; int size; int count;}; struct Ht_item* create_item(char* key, int value) { struct Ht_item* item = (struct Ht_item*) malloc (sizeof(struct Ht_item)); item->name = (char*) malloc (strlen(key) + 1); item->numberCourses = value; strcpy(item->name, key); item->numberCourses = value; return item;} struct HashTable* create_table(int size) { // Creates a New Hash Table struct HashTable* table = (struct HashTable*) malloc (sizeof(struct HashTable)); table->size = size; table->count = 0; table->items = (struct Ht_item**) calloc (table->size, sizeof(struct Ht_item*));…
Please convert to C language //quadratic probing#include <bits/stdc++.h>using namespace std; void add_using_quadratic_probing(int hash[], int a){ //hash function h(x)=x%10 int k = a % 10; //quadratic probing int incr = 1; while (true) { if (hash[k] == -1) { hash[k] = a; break; } //quadratic increment of probe k = (k + int(pow(incr, 2))) % 10; incr++; }} int main(){ //set of input numbers vector<int> arr{ 123, 124, 333, 4679, 983 }; //initialize the hash table //each entry of the hash table is a single entry int hash[10]; //size of hashtable is 10 memset(hash, -1, sizeof(hash)); //initialize with empty initially for (int a : arr) { //hashing add_using_quadratic_probing(hash, a); } cout << "---------using quadratic probing---------\n"; cout << "Hash table is:\n"; for (int i = 0; i < 10; i++) { if (hash[i] == -1) cout…
Q: Hash table is a data structure in which keys are mapped to array positions by a hash function. Theprocess of mapping the keys to appropriate locations in a hash table is called hashing. Hash functions areused to reduce the number of collisions.i. Mention the methods to minimize collision.ii. Explain the advantage of using double hashing over linear and quadratic probing techniques.iii. Load the keys given below in a hash table of size 7 in the same order using chaining with thehash function h(key)= key % 7. Show graphically how collisions are resolved using chainingin this particular case.12, 101, 3, 21, 14, 13, 16, 7, 141
PROBLEM 4-Hashing and Collision. Complete the table below. Follow-up Question: From the table above, how many synonyms are there?
Hash table is a data structure in which keys are mapped to array positions by a hash function. Theprocess of mapping the keys to appropriate locations in a hash table is called hashing. Hash functions areused to reduce the number of collisions.i. Mention the methods to minimize collision.ii. Explain the advantage of using double hashing over linear and quadratic probing techniques.iii. Load the keys given below in a hash table of size 7 in the same order using chaining with thehash function h(key)= key % 7. Show graphically how collisions are resolved using chainingin this particular case.12, 101, 3, 21, 14, 13, 16, 7, 141