You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask containing CO,(g) at 30.0°C and 750. torr. The solid BaO and MgO in the flask completely reacted to form BaCo,(s) and MgCO,(s), respectively. After the reactions to form BaCO,(s) and M9CO,(s) were completed, the pressure of CO,(g) remaining was 245 torr, still at 30.0°C. Calculate the mass of BaO(s) in the initial mixture in grams. (Assume ideal gas behavior).

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A: According to law of Ideal gas,  PV = nRT P= Pressure of gas, V= volume of gas           n= moles of…

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A: Given, Volume  = 1.25 L Temperature = 21°C = 21+273 = 294 K Pressure = 758 torr Mass of H2S = ?

Q: delete 4. 8. 5. 6. 7. R. P. E. enter H. return B alt MOSISO command option

A: Temperature is constant so  P1V1 +P2V2 = PV

Q: You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask…

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Q: The volume of a sample of nitrogen is 7.00 liters at 40oC and 740 torr. What volume will it occupy…

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Q: You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask…

A: The total mass of the mixture = 6.35g Consider the mass of BaO and MgO in the unknown sample be 'x'…

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Q: molar mass

A:

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Q: You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask…

A: Convert the given temperature that is 30 degree Celsius in kelvin as shown follows:T (K) = (30 +…

Q: You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask…

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Q: You placed 6.35 g of a mixture containing unknown amounts of BaO(s) and MgO(s) in a 3.50-L flask…

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Q: Question is attached

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.