You wish to find the enthalpy for the reaction 6 GeI₄ (s) + 14 NH₄I (s) → 3 Ge₂H₆ (l) + 7 N₂ (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H₂ (g) → Ge₂H₆ (l) ∆H = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) → GeI₄ (s) + 2 H₂(g) ∆H = -247.8 kJ/mol Equation 3: 2 NH₄I (s) → N₂ (g) + 2 HI (g) + 3 H₂(g) ∆H = 455.8 kJ/mol   D. What would be the enthalpy change for 6 GeI₄ (s) + 12 H₂(g) → 6 Ge (s) + 24 HI (g)?   E. In order to place 14 NH₄I (s) as reactants in the desired equation, what do you need to do to the third equation?   F. What would be the enthalpy change for 14 NH₄I (s) → 7 N₂ (g) + 14 HI (g) + 21 H₂(g)?

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.43QE: Another reaction that is used to propel rockets is N2O4(l)+2N2H4(l)3N2(g)+4H2O(g) This reaction has...
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You wish to find the enthalpy for the reaction
6 GeI₄ (s) + 14 NH₄I (s) → 3 Ge₂H₆ (l) + 7 N₂ (g) + 38 HI (g)
Given the following equations
Equation 1: 2 Ge (s) + 3 H₂ (g) → Ge₂H₆ (l) ∆H = 137.3 kJ/mol
Equation 2: Ge (s) + 4 HI (g) → GeI₄ (s) + 2 H₂(g) ∆H = -247.8 kJ/mol Equation 3: 2 NH₄I (s) → N₂ (g) + 2 HI (g) + 3 H₂(g) ∆H = 455.8 kJ/mol
 
D. What would be the enthalpy change for 6 GeI₄ (s) + 12 H₂(g) → 6 Ge (s) + 24 HI (g)?
 
E. In order to place 14 NH₄I (s) as reactants in the desired equation, what do you need to do to the third equation?
 
F. What would be the enthalpy change for 14 NH₄I (s) → 7 N₂ (g) + 14 HI (g) + 21 H₂(g)?
 
 
 
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