your result:- ) 0.350 M chloroacetic acid? Given, Ka=1.36x10³, Kw=1×1014 ) 0.420 M sodium chloroacetate? Given, Ka= 1.36x10-3, Kp= Kw/Ka

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Chapter17: Spontaneity, Entropy, And Free Energy
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B: At 25°C, what is the hydronium ion concentration in the following with discussing
your result:-
1) 0.350 M chloroacetic acid?
Given, Ka=1.36x103, Kw=1×1014
2) 0.420 M sodium chloroacetate?
Given, Ka= 1.36x10-3, K= Kw/Ka
Transcribed Image Text:B: At 25°C, what is the hydronium ion concentration in the following with discussing your result:- 1) 0.350 M chloroacetic acid? Given, Ka=1.36x103, Kw=1×1014 2) 0.420 M sodium chloroacetate? Given, Ka= 1.36x10-3, K= Kw/Ka
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