ZieaeuAadousaues:erausi92 Heat of Respiration of a Food Product. A fresh-food product is held in cold stor-age at 278.0 K. It is packed in a container in the shape of a flat slab with all facesinsulated except for the top flat surface, which is exposed to the air at 278.0 K. Forestimation purposes, the surface temperature will be assumed to be 278 K. The slabis 152.4 mm thick and the exposed surface area is 0.186 m2. The density of the food-stuff is 641 kg/m2. The heat of respiration is 0.070 kJ/kg h and the thermal conduc-tivity is 0.346 W/m K. Calculate the maximum temperature in the food product atsteady state and the total heat given off in W. (Note: It is assumed in this problemthat there is no air circulation inside the foodstuff. Hence, the results will be conser-vative, since circulation during respiration will reduce the temperature.)/11

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Asked Aug 29, 2019
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Ziea
euA
adousaues:
erau
si
9
2 Heat of Respiration of a Food Product. A fresh-food product is held in cold stor-
age at 278.0 K. It is packed in a container in the shape of a flat slab with all faces
insulated except for the top flat surface, which is exposed to the air at 278.0 K. For
estimation purposes, the surface temperature will be assumed to be 278 K. The slab
is 152.4 mm thick and the exposed surface area is 0.186 m2. The density of the food-
stuff is 641 kg/m2. The heat of respiration is 0.070 kJ/kg h and the thermal conduc-
tivity is 0.346 W/m K. Calculate the maximum temperature in the food product at
steady state and the total heat given off in W. (Note: It is assumed in this problem
that there is no air circulation inside the foodstuff. Hence, the results will be conser-
vative, since circulation during respiration will reduce the temperature.)
/1
1
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Ziea euA adousaues: erau si 9 2 Heat of Respiration of a Food Product. A fresh-food product is held in cold stor- age at 278.0 K. It is packed in a container in the shape of a flat slab with all faces insulated except for the top flat surface, which is exposed to the air at 278.0 K. For estimation purposes, the surface temperature will be assumed to be 278 K. The slab is 152.4 mm thick and the exposed surface area is 0.186 m2. The density of the food- stuff is 641 kg/m2. The heat of respiration is 0.070 kJ/kg h and the thermal conduc- tivity is 0.346 W/m K. Calculate the maximum temperature in the food product at steady state and the total heat given off in W. (Note: It is assumed in this problem that there is no air circulation inside the foodstuff. Hence, the results will be conser- vative, since circulation during respiration will reduce the temperature.) /1 1

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Step 1

Calculate the maximum temperature of the food product at steady state.

T T
2k
max
278 K +(0.070kJ/kg h)(0.1524 m)
2(0.346W/m K)
(12.464 J/m2 s)(0.1524 m)
2(0.346W/m K)
-278 K
=278.42 K
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T T 2k max 278 K +(0.070kJ/kg h)(0.1524 m) 2(0.346W/m K) (12.464 J/m2 s)(0.1524 m) 2(0.346W/m K) -278 K =278.42 K

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Step 2

Calculate the total h...

Q qV
=(12.464J/m2.s)x (0.186 m2x 0.1524 m
= 0.353 W
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Q qV =(12.464J/m2.s)x (0.186 m2x 0.1524 m = 0.353 W

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