Answered: P L1 L2 Clevis and pin 1 a= 0,6 m T.…

P L1 L2 Clevis and pin 1 a= 0,6 m T. Clevis and pin 2 -2.0 m -b = 1.0 m. Center of gravity of plate Steel plate (2.5 x 1.5 x 0,08 m) PROBLEM 1.8-6

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter8: Centroids And Distributed Loads

Section: Chapter Questions

Problem 8.7P: Using integration, locate the centroid of the area under the n-th order parabola in terms of b, h,...

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Buckling of columns

The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.

Question

A steel plate of dimensions 2.5 x 1.5 x 0.08 m and weighing 23.1 kN is hoisted by steel cables with lengths L1 = 3.2 m and L2 = 3.9 m that are each attached to the plate by a clevis and pin (see figure). The pins through the clevises are 18 mm in diameter and are located 2.0 m apart. The orientation angles are measured to be s = 94.4' and a = 54.9° For these conditions, first determine the cable forces T1 and T2, then find the average shear stress Taver in both pin 1 and pin 2, and then the average bearing stress ?? between the steel plate and each pin. Ignore the weight of the cables.

P
L1
L2
Clevis
and pin 1
a= 0,6 m
T.
Clevis
and pin 2
-2.0 m
-b = 1.0 m.
Center of gravity
of plate
Steel plate
(2.5 x 1.5 x 0,08 m)
PROBLEM 1.8-6

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