   Chapter 10, Problem 77AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# For each of the substances listed in Table 10.1, calculate the quantity of heat required to heat 150. g of the substance by 11.2°C.

Interpretation Introduction

Interpretation:

The heat required to raise the temperature of each substance in table 10.1 should be calculated.

Concept Introduction:

The specific heat is defined as the amount of heat per unit mass needed to raise the temperature by one degree Celsius.

It is mathematically represented as follows:

Q=msΔT

Here, Q is heat, m is mass, s is specific heat capacity and ΔT is change in temperature.

Explanation

Given Information:

The mass of each substance is 150 g and the change in temperature is 11.2 C.

Calculation:

Table 10.1 is as follows:

 Substance Specific heat capacity (J/g ∘C) Water (liquid) 4.184 Water (ice) 2.03 Water (steam) 2.0 Aluminium 0.89 Iron 0.45 Mercury 0.14 Carbon 0.71 Silver 0.24 Gold 0.13

From table 10.1, the specific heat capacity of water (liquid) is 4.184 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

On putting the values,

Q=(150 g)(4.184 J/g C)(11.2 C)=7029.12 J

Thus, the heat required to raise the temperature of liquid water is 7029.12 J.

From table 10.1, the specific heat capacity of water (ice) is 2.03 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

On putting the values,

Q=(150 g)(2.03 J/g C)(11.2 C)=3410.4 J

Thus, the heat required to raise the temperature of solid water (ice) is 3410.4 J.

From table 10.1, the specific heat capacity of water (steam) is 2.0 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

On putting the values,

Q=(150 g)(2.0 J/g C)(11.2 C)=3360 J

Thus, the heat required to raise the temperature of gaseous water (steam) is 3360 J.

From table 10.1, the specific heat capacity of aluminium is 0.89 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

On putting the values,

Q=(150 g)(0.89 J/g C)(11.2 C)=1495.2 J

Thus, the heat required to raise the temperature of aluminium is 1495.2 J.

From table 10.1, the specific heat capacity of iron is 0.45 J/g C

The heat required can be calculated using the following equation:

Q=msΔT

On putting the values,

Q=(150 g)(0

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