   # Calculate the pH of each of the following solutions. a. 0.12 M KNO 2 b. 0.45 M NaOCl c. 0.40 M NH 4 ClO 4 ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 13, Problem 120E
Textbook Problem
1 views

## Calculate the pH of each of the following solutions.a. 0.12 M KNO2b. 0.45 M NaOClc. 0.40 M NH4ClO4

(a)

Interpretation Introduction

Interpretation: The pH value for each of the given solutions to be calculated.

Concept introduction: The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

At equilibrium, the equilibrium constant expression is expressed by the formula,

Ka=ConcentrationofproductsConcentrationofreactants

The value of Kw is calculated by the formula,

Kw=KaKb

To determine: The pH value for each of the given solution of 0.12M KNO2 .

### Explanation of Solution

Explanation

The equilibrium constant expression for the given reaction is, Kb=[HNO2][OH][NO2]

The dominant equilibrium reaction is,

NO2(aq)HNO2(aq)+OH(aq)

At equilibrium, the equilibrium constant expression is expressed by the formula,

Kb=ConcentrationofproductsConcentrationofreactants

Where,

• Kb is the base ionization constant.

The equilibrium constant expression for the given reaction is,

Kb=[HNO2][OH][NO2] (1)

The Kb value is 2.5×10-11_ .

The value, Kw=KaKb

The value of Ka for HNO2 is 4.0×104 .

The value of Kb is calculated by the formula,

Kb=KwKa

Substitute the value of Ka in the above expression.

Kb=1.0×10144.0×104=2.5×10-11_

The [OH] is 1.73×10-6M_ .

The change in concentration of NO2 is assumed to be x .

The liquid components do not affect the value of the rate constant.

The ICE table for the stated reaction is,

NO2(aq)HNO2(aq)+OH(aq)Inititialconcentration0.1200Changex+x+xEquilibriumconcentration0.12xxx

The equilibrium concentration of [NO2] is (0

(b)

Interpretation Introduction

Interpretation: The pH value for each of the given solutions to be calculated.

Concept introduction: The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

At equilibrium, the equilibrium constant expression is expressed by the formula,

Ka=ConcentrationofproductsConcentrationofreactants

The value of Kw is calculated by the formula,

Kw=KaKb

To determine: The pH value for each of the given solution of 0.45M NaOCl .

(c)

Interpretation Introduction

Interpretation: The pH value for each of the given solutions to be calculated.

Concept introduction: The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

At equilibrium, the equilibrium constant expression is expressed by the formula,

Ka=ConcentrationofproductsConcentrationofreactants

The value of Kw is calculated by the formula,

Kw=KaKb

To determine: The pH value for each of the given solution of 0.40M NH4ClO4 .

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Divide into two groups. One group will argue in support of using superfoods, and one group will argue against t...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Four properties of gases may be measured. Name them.

Introductory Chemistry: An Active Learning Approach

What organisms can affect coastal configuration?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin

If a human ear canal can be thought of as resembling an organ pipe, closed at one end, that resonates at a fund...

Physics for Scientists and Engineers, Technology Update (No access codes included) 