   Chapter 13, Problem 1ALQ ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
70 views

# s you increase the temperature of a gas in a sealed, rigid container, what happens to the density of the gas? Would the results be the same if you did the same experiment in a container with a movable piston at a constant external pressure? Explain.

Interpretation Introduction

Interpretation:

The affect on the density of the gas should be determined when the temperature of gas in a sealed, rigid container increases.

Whether the results will be the same when the same experiment in a container with a movable piston at a constant external pressure takes place should be explained.

Concept introduction:

The results can be explained using the ideal gas law.

The ideal gas equation:

PV = nRT

Where, V is the volume of the gas.

P is the pressure of the gas.

n is the number of moles of the gas.

R is the gas constant.

and T is the temperature.

In first experiment density of the gas will remain the same

In the second experiment density of the gas will decrease.

Explanation

The ideal gas equation

PV = nRT

or n/V = P/RT

Or, P/RT = d (where d is the density of the gas)

An increase in temperature will normally cause an increase in the volume. However, because the gas is enclosed in a rigid container the volume of the container cannot increase. Therefore, due to the increase in temperature, molecular momentum of air molecules also increases which further results in increase in the pressure inside container. Now, the density of a gas is the ratio of mass to its volume. If neither the mass nor the volume change as the can is heated, there will be no change in the density of the gas.

When the gas is heated in a container with a movable piston, the volume of the gas will also increase. Now, density is defined as d = m/V. Therefore, an increase in the volume will cause a decrease in the density of the gas.

Conclusion

Therefore, based on the ideal gas equation, when the gas is heated in a sealed container the density of the gas will remain constant.

However, when the gas is heated in a container with a movable piston, the density of the gas will decrease.

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