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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 14, Problem 59E
Textbook Problem
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Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 × 10−5) by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added.

a. 0.0 mL

b. 50.0 mL

c. 100.0 mL

d. 150.0 mL

e. 200.0 mL

f. 250.0 mL

(a)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 0.0mL KOH has been added to it.

Explanation of Solution

Explanation

The concentration of H+ .is 0.00189M_ .

Given:

The concentration of Acetic acid is 0.200M .

The concentration of KOH is 0.100M .

The volume of Acetic acid is 100.0mL .

The volume of KOH is 0.0mL .

The value of Ka of Acetic acid is 1.8×105

The conversion of mL into L is done as,

1mL=0.001L

Hence the conversion of 100mL into L is done as,

100mL=100×0.001L=0.100L

The concentration of any species is given as,

Concentration=NumberofmolesVolumeofsolutioninlitres (1)

Rearrange the above equation to obtain the value of number of moles.

Numberofmoles=Concentration×Volumeofsolutioninlitres (2)

Substitute the concentration and volume of CH3COOH in the above equation as,

Numberofmoles=Concentration×Volumeofsolutioninlitres=0.200M×0.1L=0.02moles

Make the ICE table for the reaction between CH3COOH and KOH .

CH3COOH+KOHCH3COOK++H2OInitial moles:0.0200Change:00+0.02Finalmoles:0.0200.02

The above equation shows the presence of equilibrium condition in the solution.

Make the ICE table for the dissociation reaction of CH3COOH .

CH3COOHCH3COOH+Initial(M):0.200Change(M):xxxEquilibrium(M):0

(b)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 50.0mL KOH has been added to it.

(c)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 100.0mL KOH has been added to it.

(d)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 150.0mL KOH has been added to it.

(e)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 200.0mL KOH has been added to it.

(f)

Interpretation Introduction

Interpretation: The titration of Acetic acid with different volumes of KOH is given. The pH of each solution is to be calculated.

Concept introduction: Titration is a quantitative chemical analysis method that is used for the determination of concentration of an unknown solution. In acid base titration, the neutralization of either acid or base is done with a base or acid respectively of known concentration. This helps to determine the unknown concentration of acid or base.

When the amount of the titrant added is just sufficient for the neutralization of analyte is called equivalence point. At this point equal equivalents of both the acid and base are added.

To determine: The value of pH of solution when 250.0mL KOH has been added to it.

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Chapter 14 Solutions

Chemistry: An Atoms First Approach
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Ch. 14 - What are the major species in solution after...Ch. 14 - A friend asks the following: Consider a buffered...Ch. 14 - Mixing together solutions of acetic acid and...Ch. 14 - Could a buffered solution be made by mixing...Ch. 14 - Sketch two pH curves, one for the titration of a...Ch. 14 - Sketch a pH curve for the titration of a weak acid...Ch. 14 - You have a solution of the weak acid HA and add...Ch. 14 - You have a solution of the weak acid HA and add...Ch. 14 - The common ion effect for weak acids is to...Ch. 14 - Consider a buffer solution where [weak acid] ...Ch. 14 - A best buffer has about equal quantities of weak...Ch. 14 - Consider the following pH curves for 100.0 mL of...Ch. 14 - An acid is titrated with NaOH. The following...Ch. 14 - Consider the following four titrations. i. 100.0...Ch. 14 - Figure 14-4 shows the pH curves for the titrations...Ch. 14 - Acidbase indicators mark the end point of...Ch. 14 - How many of the following are buffered solutions?...Ch. 14 - Which of the following can be classified as buffer...Ch. 14 - A certain buffer is made by dissolving NaHCO3 and...Ch. 14 - A buffer is prepared by dissolving HONH2 and...Ch. 14 - Calculate the pH of each of the following...Ch. 14 - Calculate the pH of each of the following...Ch. 14 - Compare the percent dissociation of the acid in...Ch. 14 - Compare the percent ionization of the base in...Ch. 14 - Calculate the pH after 0.020 mole of HCl is added...Ch. 14 - Calculate the pH after 0.020 mole of HCl is added...Ch. 14 - Calculate the pH after 0.020 mole of NaOH is added...Ch. 14 - Calculate the pH after 0.020 mole of NaOH is added...Ch. 14 - Which of the solutions in Exercise 21 shows the...Ch. 14 - Which of the solutions in Exercise 22 is a...Ch. 14 - Calculate the pH of a solution that is 1.00 M HNO2...Ch. 14 - Calculate the pH of a solution that is 0.60 M HF...Ch. 14 - Calculate the pH after 0.10 mole of NaOH is added...Ch. 14 - Calculate the pH after 0.10 mole of NaOH is added...Ch. 14 - Calculate the pH of each of the following buffered...Ch. 14 - Calculate the pH of each of the following buffered...Ch. 14 - Calculate the pH of a buffered solution prepared...Ch. 14 - A buffered solution is made by adding 50.0 g NH4Cl...Ch. 14 - Calculate the pH after 0.010 mole of gaseous HCl...Ch. 14 - An aqueous solution contains dissolved C6H5NH3Cl...Ch. 14 - Calculate the mass of sodium acetate that must be...Ch. 14 - What volumes of 0.50 M HNO2 and 0.50 M NaNO2 must...Ch. 14 - Consider a solution that contains both C5H5N and...Ch. 14 - Calculate the ratio [NH3]/[NH4+] in...Ch. 14 - Carbonate buffers are important in regulating the...Ch. 14 - When a person exercises, muscle contractions...Ch. 14 - Consider the acids in Table 13-2. Which acid would...Ch. 14 - Consider the bases in Table 13-3. Which base would...Ch. 14 - Calculate the pH of a solution that is 0.40 M...Ch. 14 - Calculate the pH of a solution that is 0.20 M HOCl...Ch. 14 - Which of the following mixtures would result in...Ch. 14 - Which of the following mixtures would result in a...Ch. 14 - What quantity (moles) of NaOH must be added to 1.0...Ch. 14 - Calculate the number of moles of HCl(g) that must...Ch. 14 - Consider the titration of a generic weak acid HA...Ch. 14 - Sketch the titration curve for the titration of a...Ch. 14 - Consider the titration of 40.0 mL of 0.200 M HClO4...Ch. 14 - Consider the titration of 80.0 mL of 0.100 M...Ch. 14 - Consider the titration of 100.0 mL of 0.200 M...Ch. 14 - Consider the titration of 100.0 mL of 0.100 M...Ch. 14 - Lactic acid is a common by-product of cellular...Ch. 14 - Repeat the procedure in Exercise 61, but for the...Ch. 14 - Repeat the procedure in Exercise 61, but for the...Ch. 14 - Repeat the procedure in Exercise 61, but for the...Ch. 14 - Calculate the pH at the halfway point and at the...Ch. 14 - In the titration of 50.0 mL of 1.0 M methylamine,...Ch. 14 - You have 75.0 mL of 0.10 M HA. After adding 30.0...Ch. 14 - A student dissolves 0.0100 mole of an unknown weak...Ch. 14 - Two drops of indicator HIn (Ka = 1.0 109), where...Ch. 14 - Methyl red has the following structure: It...Ch. 14 - Potassium hydrogen phthalate, known as KHP (molar...Ch. 14 - A certain indicator HIn has a pKa of 3.00 and a...Ch. 14 - Which of the indicators in Fig. 14-8 could be used...Ch. 14 - Which of the indicators in Fig. 14-8 could be used...Ch. 14 - Which of the indicators in Fig. 14-8 could be used...Ch. 14 - Which of the indicators in Fig. 14-8 could be used...Ch. 14 - Estimate the pH of a solution in which bromcresol...Ch. 14 - Estimate the pH of a solution in which crystal...Ch. 14 - A solution has a pH of 7.0. What would be the...Ch. 14 - A solution has a pH of 4.5. What would be the...Ch. 14 - Derive an equation analogous to the...Ch. 14 - a. Calculate the pH of a buffered solution that is...Ch. 14 - Tris(hydroxymethyl)aminomethane, commonly called...Ch. 14 - You make 1.00 L of a buffered solution (pH = 4.00)...Ch. 14 - You have the following reagents on hand: Solids...Ch. 14 - Amino acids are the building blocks for all...Ch. 14 - Phosphate buffers are important in regulating the...Ch. 14 - What quantity (moles) of HCl(g) must be added to...Ch. 14 - Calculate the value of the equilibrium constant...Ch. 14 - The following plot shows the pH curves for the...Ch. 14 - Calculate the volume of 1.50 102 M NaOH that must...Ch. 14 - Repeat the procedure in Exercise 61, but for the...Ch. 14 - A certain acetic acid solution has pH = 2.68....Ch. 14 - A 0.210-g sample of an acid (molar mass = 192...Ch. 14 - The active ingredient in aspirin is...Ch. 14 - One method for determining the purity of aspirin...Ch. 14 - A student intends to titrate a solution of a weak...Ch. 14 - A student titrates an unknown weak acid, HA, to a...Ch. 14 - A sample of a certain monoprotic weak acid was...Ch. 14 - Consider 1.0 L of a solution that is 0.85 M HOC6H5...Ch. 14 - What concentration of NH4Cl is necessary to buffer...Ch. 14 - Consider the following acids and bases: HCO2H Ka =...Ch. 14 - Consider a buffered solution containing CH3NH3Cl...Ch. 14 - Consider the titration of 150.0 mL of 0.100 M HI...Ch. 14 - Consider the titration of 100.0 mL of 0.100 M HCN...Ch. 14 - Consider the titration of 100.0 mL of 0.200 M...Ch. 14 - Consider the following four titrations (iiv): i....Ch. 14 - Another way to treat data from a pH titration is...Ch. 14 - A buffer is made using 45.0 mL of 0.750 M HC3H5O2...Ch. 14 - A 0.400-M solution of ammonia was titrated with...Ch. 14 - What volume of 0.0100 M NaOH must be added to 1.00...Ch. 14 - Consider a solution formed by mixing 50.0 mL of...Ch. 14 - When a diprotic acid, H2A, is titrated with NaOH,...Ch. 14 - Consider the following two acids: In two separate...Ch. 14 - The titration of Na2CO3 with HCl bas the following...Ch. 14 - Consider the titration curve in Exercise 115 for...Ch. 14 - A few drops of each of the indicators shown in the...Ch. 14 - Malonic acid (HO2CCH2CO2H) is a diprotic acid. In...Ch. 14 - A buffer solution is prepared by mixing 75.0 mL of...Ch. 14 - A 10.00-g sample of the ionic compound NaA, where...Ch. 14 - Calculate the pH of a solution prepared by mixing...Ch. 14 - Consider a solution prepared by mixing the...

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