Many metal ions are precipitated from solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution. CuSO4(aq) + Na2S(aq)-> CuS(s) + Na2SO4(aq) What volume of 0.144 M Na2S solution would be required to precipitate all of the copper(II) ion from 27.6 mL of 0.100 M CuSO4 solution?
Many metal ions are precipitated from solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution. CuSO4(aq) + Na2S(aq)-> CuS(s) + Na2SO4(aq) What volume of 0.144 M Na2S solution would be required to precipitate all of the copper(II) ion from 27.6 mL of 0.100 M CuSO4 solution?
Introductory Chemistry: A Foundation
8th Edition
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter15: Solutions
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Problem 126AP: You pour 150.0 mL of a 0.250 M lead(ll) nitrate solution into an empty 500-mL flask. What is the...
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Many metal ions are precipitated from solution by the sulfide ion. As an example, consider treating a solution of copper(II) sulfate with sodium sulfide solution.
CuSO4(aq) + Na2S(aq)-> CuS(s) + Na2SO4(aq)
What volume of 0.144 M Na2S solution would be required to precipitate all of the copper(II) ion from 27.6 mL of 0.100 M CuSO4 solution?
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