   Chapter 15, Problem 92AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# 92. If 500. g of water is added to 75 g of 25% NaCl solution, what is the percent by mass of NaCl in the diluted solution?

Interpretation Introduction

Interpretation:

The percent by mass of NaCl in the diluted solution is to be calculated.

Concept Introduction:

Solution is composed of solute and solvent particles. Solute particles are always present in lower amount as compared to amount of the solvent in the solution. The solution can be concentrated and diluted on the basis of number of moles of solute present in the particular amount of the solvent.

The formula used;

MassofNaCl=Massofsolution×Mass%ofNaCl100.

Explanation

The mass and mass percent of NaCl solution is given to be 75g and 25% respectively.

The mass of water in the solution is given to be 500.g.

The mass of NaCl in the solution is calculated by the formula,

MassofNaCl=Massofsolution×Mass%ofNaCl100        (1)

Substitute the values of mass of solution and mass % of NaCl in the equation (1).

MassofNaCl=75g×25100=18.75g

The water having amount 500.g is added to 18.75g of NaCl.

The total mass of the solution is calculated by the formula,

Totalmassofsolution=MassofWater+MassofNaCl        (2)

Substitute the values of mass of water and NaCl in the equation (2)

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