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Look up the reduction potential for Fe 3+ to Fe 2+ . Look up the reduction potential for Fe 2+ to Fe. Finally, look up the reduction potential for Fe 3+ to Fe. You should notice that adding the reduction potentials for the first two does not give the potential for the third. Why not? Show how you can use the first two potentials to calculate the third potential.

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 17, Problem 12ALQ
Textbook Problem
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Look up the reduction potential for Fe3+ to Fe2+. Look up the reduction potential for Fe2+ to Fe. Finally, look up the reduction potential for Fe3+ to Fe. You should notice that adding the reduction potentials for the first two does not give the potential for the third. Why not? Show how you can use the first two potentials to calculate the third potential.

Interpretation Introduction

Interpretation:

The reduction potential values for conversion of Fe3+ to Fe2+ , Fe2+ to Fe and Fe3+ to Fe are given. The non-additive nature of cell potential and calculation of cell potential for equation Fe3+ to Fe using first two equations is to be stated.

Concept introduction:

The intensive properties are non-additive in nature whereas the extensive properties are easily added.

The addition of change in Gibbs free energy for each half reaction gives the value of overall cell potential.

To determine: The experiment that can determine if a reaction is spontaneous or not and the relationship between spontaneity and the final equilibrium position of a reaction.

Explanation of Solution

The addition of the reduction potential of the first two reactions does not give the reduction potential for the third reaction because the reduction potential is intensive in nature and intensive properties do not possess additive nature.

The given reactions are as follows,

Fe3+(aq)+eFe2+(aq)E°=0.77V (1)

Fe2+(aq)+2eFe(s)E°=0.44V (2)

Fe3+(aq)+3eFe(s)E°=0.036V (3)

Add the equation (1) and (2) . The final equation formed is,

Fe3+(aq)+3eFe(s)

E°=0.77V+(0.44V)

E°=0.33V_

This value of potential is different from the one given in equation (3) . Therefore reduction potential cannot be added normally.

The value of cell potential calculated by adding change in Gibbs free energy is -0.036V_ .

The given reactions are as follows,

Fe3+(aq)+eFe2+(aq)E°=0.77V (1)

Fe2+(aq)+2eFe(s)E°=0

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Chapter 17 Solutions

Chemistry: An Atoms First Approach
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