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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

Given the following two standard reduction potentials,

Chapter 18, Problem 150CP, Given the following two standard reduction potentials, solve for the standard reduction potential of

solve for the standard reduction potential of the half-reaction

M 3 + + e M 2 +

(Hint: You must use the extensive property ∆G° to determine the standard reduction potential.)

Interpretation Introduction

Interpretation:

The standard reduction potential of two half-cells is given. The standard reduction potential for the given half-reaction is to be calculated.

Concept introduction:

The standard reduction potential is the potential of the cell at the standard conditions like 1.0M concentration and a pressure of 1atm at the given temperature conditions.

To determine: The standard reduction potential of the given half-cell reaction.

Explanation

The given reactions are as follows,

M3++3eME°=0.10V (1)

M2++2eME°=0.50V (2)

Subtract both the equations to obtain the given reaction as,

M3++eM2+ (3)

The cell potential for the equation (3) is calculated using the relationship between cell potential and change in Gibbs free energy, ΔG°=nFE° .

Where the following terms are defined as follows,

  • ΔG° is the change in Gibbs free energy.
  • n is the number of electrons involved in the cell reaction.
  • F is the Faraday’s constant (96485C/molee) .
  • E° is the cell potential.

The change in Gibbs free energy for equation (1) is calculated as follows,

ΔG°1=-nFE°1=-(3)×96485×(-0.10V)=28,945

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Chapter 18 Solutions

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