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ChemistryChemistry & Chemical Reactivity10th Edition

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Chapter 2, Problem 139GQ
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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Solutions

Chapter
Section
Problem 1PS
Problem 2PS
Problem 3PS
Problem 4PS
Problem 5PS
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Problem 101GQ
Problem 102GQ
Problem 103GQ
Problem 104GQ
Problem 105GQ
Problem 106GQ
Problem 107GQ
Problem 108GQ
Problem 109GQ
Problem 110GQ
Problem 111GQ
Problem 112GQ
Problem 113GQ
Problem 114GQ
Problem 115GQ
Problem 116GQ
Problem 117GQ
Problem 118GQ
Problem 119GQ
Problem 120GQ
Problem 121GQ
Problem 122GQ
Problem 123GQ
Problem 124GQ
Problem 125GQ
Problem 126GQ
Problem 127GQ
Problem 128GQ
Problem 129GQ
Problem 130GQ
Problem 131GQ
Problem 132GQ
Problem 133GQ
Problem 134GQ
Problem 135GQ
Problem 136GQ
Problem 137GQ
Problem 138GQ
Problem 139GQ
Problem 140GQ
Problem 141GQ
Problem 142GQ
Problem 143GQ
Problem 144GQ
Problem 145GQ
Problem 146GQ
Problem 147GQ
Problem 148GQ
Problem 149GQ
Problem 150GQ
Problem 151GQ
Problem 152GQ
Problem 153GQ
Problem 154GQ
Problem 155GQ
Problem 156GQ
Problem 157GQ
Problem 158GQ
Problem 159IL
Problem 160IL
Problem 161IL
Problem 162IL
Problem 163IL
Problem 164IL
Problem 165SCQ
Problem 166SCQ
Problem 167SCQ
Problem 168SCQ
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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Chromium is obtained by heating chromium(III) oxide with carbon. Calculate the mass percent of chromium in the oxide, and then use this value to calculate the quantity of Cr2O3 required to produce 850 kg of chromium metal.

Interpretation Introduction

Interpretation: The mass percent of chromium in Cr2O3 and the mass of Cr2O3 that must be used to produce 850  kg of chromium have to be determined.

Concept introduction:

  • Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12 g of 12C.
  • From given mass of substance moles could be calculated by using the following formula,

    Moles of substance  = Given mass of substanceMolecular mass

  • The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol)
  • Mass percentage is one way to represent the concentration of an element in a compound or a component in a mixture. Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.
Explanation

Mass percent of elements of a compound is the ratio of mass of element to the mass of whole compound and multiplied with hundred.

The molecular formula of chromium (III) oxide is Cr2O3 and its molar mass is 152 g/mol

Then, the mass percent of chromium in Cr2O3 can be calculated as follows,

Molar Mass  of  Cr  in the  compound  =  2 × 52 =  104  g/mol Mass  percent  of  Cr in   Cr2O3 =  Molar  mass  of   Cr

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Sect-2.1 P-2.1CYUSect-2.2 P-2.2CYUSect-2.2 P-2.3CYUSect-2.5 P-2.4CYUSect-2.5 P-2.5CYUSect-2.6 P-2.6CYUSect-2.6 P-2.7CYUSect-2.7 P-2.8CYUSect-2.7 P-2.9CYUSect-2.7 P-2.10CYU
Sect-2.7 P-2.11CYUSect-2.8 P-2.12CYUSect-2.8 P-1.1ACPSect-2.8 P-1.2ACPSect-2.8 P-2.1ACPSect-2.8 P-2.2ACPSect-2.8 P-3.1ACPSect-2.8 P-3.2ACPSect-2.8 P-3.3ACPSect-2.8 P-3.4ACPCh-2 P-1PSCh-2 P-2PSCh-2 P-3PSCh-2 P-4PSCh-2 P-5PSCh-2 P-6PSCh-2 P-7PSCh-2 P-8PSCh-2 P-9PSCh-2 P-10PSCh-2 P-11PSCh-2 P-12PSCh-2 P-13PSCh-2 P-14PSCh-2 P-15PSCh-2 P-16PSCh-2 P-17PSCh-2 P-18PSCh-2 P-19PSCh-2 P-20PSCh-2 P-21PSCh-2 P-22PSCh-2 P-23PSCh-2 P-24PSCh-2 P-25PSCh-2 P-26PSCh-2 P-27PSCh-2 P-28PSCh-2 P-29PSCh-2 P-30PSCh-2 P-31PSCh-2 P-32PSCh-2 P-33PSCh-2 P-34PSCh-2 P-35PSCh-2 P-36PSCh-2 P-37PSCh-2 P-38PSCh-2 P-39PSCh-2 P-40PSCh-2 P-41PSCh-2 P-42PSCh-2 P-43PSCh-2 P-44PSCh-2 P-45PSCh-2 P-46PSCh-2 P-47PSCh-2 P-48PSCh-2 P-49PSCh-2 P-50PSCh-2 P-51PSCh-2 P-52PSCh-2 P-53PSCh-2 P-54PSCh-2 P-55PSCh-2 P-56PSCh-2 P-57PSCh-2 P-58PSCh-2 P-59PSCh-2 P-60PSCh-2 P-61PSCh-2 P-62PSCh-2 P-63PSCh-2 P-64PSCh-2 P-65PSCh-2 P-66PSCh-2 P-67PSCh-2 P-68PSCh-2 P-69PSCh-2 P-70PSCh-2 P-71PSCh-2 P-72PSCh-2 P-73PSCh-2 P-74PSCh-2 P-75PSCh-2 P-76PSCh-2 P-77PSCh-2 P-78PSCh-2 P-79PSCh-2 P-80PSCh-2 P-81PSCh-2 P-82PSCh-2 P-83PSCh-2 P-84PSCh-2 P-85PSCh-2 P-86PSCh-2 P-87PSCh-2 P-88PSCh-2 P-89PSCh-2 P-90PSCh-2 P-91PSCh-2 P-92PSCh-2 P-93PSCh-2 P-94PSCh-2 P-95PSCh-2 P-96PSCh-2 P-97PSCh-2 P-98PSCh-2 P-99PSCh-2 P-100PSCh-2 P-101GQCh-2 P-102GQCh-2 P-103GQCh-2 P-104GQCh-2 P-105GQCh-2 P-106GQCh-2 P-107GQCh-2 P-108GQCh-2 P-109GQCh-2 P-110GQCh-2 P-111GQCh-2 P-112GQCh-2 P-113GQCh-2 P-114GQCh-2 P-115GQCh-2 P-116GQCh-2 P-117GQCh-2 P-118GQCh-2 P-119GQCh-2 P-120GQCh-2 P-121GQCh-2 P-122GQCh-2 P-123GQCh-2 P-124GQCh-2 P-125GQCh-2 P-126GQCh-2 P-127GQCh-2 P-128GQCh-2 P-129GQCh-2 P-130GQCh-2 P-131GQCh-2 P-132GQCh-2 P-133GQCh-2 P-134GQCh-2 P-135GQCh-2 P-136GQCh-2 P-137GQCh-2 P-138GQCh-2 P-139GQCh-2 P-140GQCh-2 P-141GQCh-2 P-142GQCh-2 P-143GQCh-2 P-144GQCh-2 P-145GQCh-2 P-146GQCh-2 P-147GQCh-2 P-148GQCh-2 P-149GQCh-2 P-150GQCh-2 P-151GQCh-2 P-152GQCh-2 P-153GQCh-2 P-154GQCh-2 P-155GQCh-2 P-156GQCh-2 P-157GQCh-2 P-158GQCh-2 P-159ILCh-2 P-160ILCh-2 P-161ILCh-2 P-162ILCh-2 P-163ILCh-2 P-164ILCh-2 P-165SCQCh-2 P-166SCQCh-2 P-167SCQCh-2 P-168SCQ

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