   Chapter 2, Problem 143GQ

Chapter
Section
Textbook Problem

Iron pyrite, often called “fool’s gold,” has the formula FeS2. If you could convert 15.8 kg of iron pyrite to iron metal, what mass of the metal would you obtain?

Interpretation Introduction

Interpretation: The mass of iron metal obtained from the given amount of iron pyrite has to be calculated.

Concept introduction:

Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12g of 12C.

From given mass of substance moles could be calculated by using the following formula,

Molesofsubstance GivenmassofsubstanceMolecularmass

Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is kg/mol. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in amu.

Explanation

The amount of iron pyrite is given that 15.8kg=15800g.

The molar mass of iron pyrite is 119.98g/mol.

Conversion formula for mass of a molecule into number moles,

Numberofmoles=MassingramsMolarmass

Therefore, the number moles of iron pyrite is,

Numberofmoles=15800g119.98g/mol=131.6886mol

The molar mass of iron is 55

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 