   Chapter 2, Problem 4PS

Chapter
Section
Textbook Problem

A gold atom has a radius of 145 pm. If you could string gold atoms like beads on a thread, how many atoms would you need to have a necklace 36 cm long?

Interpretation Introduction

Interpretation:

The radius of gold atom is given that 145pm, the number of gold atoms required to make a 36cm long necklace has to be determined.

Concept introduction:

The sum of diameters of all beads on a thread is equals to the perimeter of necklace (beads are closely arranged in the string).

Explanation

The radius of the gold atom is given that 145pm, so the diameter of the gold atom is 290pm=290×10-12m.

The perimeter of necklace is 36cm=36×10-2m.

Suppose the beads are closely arranged in the string, the sum of diameters of all beads on a thread is equals to the perimeter of necklace

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 