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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
ISBN: 9781305079243
Textbook Problem

Write Lewis structures for the following. Show all resonance structures where applicable.

a. NO2, NO3, N2O4 (N2O4 exists as O2N8NO2.)

b. OCN, SCN, N3 (Carbon is the central atom in OCN and SCN.)

Interpretation Introduction

Interpretation: The Lewis and resonance structure is to be drawn for the given molecules.

Concept introduction: The Lewis structure is also known as dot structure. This structure depicts the bonding between atoms and the lone pairs of electrons if exists.

The octet rule states that atoms or molecules gain or lose electrons to get the electronic configuration of nearest noble gas.

Resonance structure is defined as the forms of a molecule having the same chemical connectivity but different distribution pattern for electrons around the structure.

Explanation

(a)

To determine: The Lewis and resonance structure of the molecule NO2,NO3 and N2O4

  • To determine: The Lewis and resonance structure of the molecule NO2,

The first step in determining the Lewis structure is to determine the number of valence electrons. The atomic number of nitrogen (N) is 7 and its electronic configuration is,

1s22s22p3

The valence electron of nitrogen is 5

The atomic number of oxygen (O) is 8 and its electronic configuration is,

1s22s22p4

The valence electron of oxygen is 6

The molecule NO2 is made of two oxygen atoms and one nitrogen atom. Also oxygen atom contains one negative charge; hence, the total number of valence electrons is,

N+2O+1e=5+2×6+1=18

The Lewis structure of NO2 is

Figure 1

The NO2 exists in two resonance structure that is

Figure 2

  • To determine: The Lewis and resonance structure of the molecule NO3.

The first step in determining the Lewis structure is to determine the number of valence electrons. The atomic number of nitrogen (N) is 7 and its electronic configuration is,

1s22s22p3

The valence electron of nitrogen is 5

The atomic number of oxygen (O) is 8 and its electronic configuration is,

1s22s22p4

The valence electron of oxygen is 6

The molecule NO3 is made of three oxygen atoms and one nitrogen atom. Also oxygen atom contains one negative charge; hence, the total number of valence electrons is,

N+3O+1e=5+3×6+1=24

The Lewis structure of NO3 is

Figure 3

The NO3 exists in three resonance structure that is

Figure 4

  • To determine: The Lewis and resonance structure of the molecule N2O4.

The first step in determining the Lewis structure is to determine the number of valence electrons. The atomic number of nitrogen (N) is 7 and its electronic configuration is,

1s22s22p3

The valence electron of nitrogen is 5

The atomic number of oxygen (O) is 8 and its electronic configuration is,

1s22s22p4

The valence electron of oxygen is 6

The molecule N2O4 is made of four oxygen atoms and two nitrogen atom. Also oxygen atom contains one negative charge; hence, the total number of valence electrons is,

2N+4O+1e=2×5+4×6=34

The Lewis structure of N2O4 is

Figure 5

The N2O4 exists in two resonance structure that is

Figure 6

(b)

To determine: The Lewis and resonance structure of the molecule OCN,SCN and N3

The Lewis and resonance structures of given molecules are as follows

The Lewis structure of OCN is

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