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A long solenoid has n = 400 turns per meter and carries a current given by I = 30.0(1 −e−1.60t), where I is in amperes and t is in seconds. Inside the solenoid and coaxial with it is a coil that has a radius of R = 6.00 cm and consists of a total of N = 250 turns of fine wire (Fig. P30.4). What emf is induced in the coil by the changing current?
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- uppose you are working on a science lab in which your professor asks you to turn a knob 750 on the detector you are using. Unfortunately, you have been working in radians for a while, so you are having trouble remembering how far to turn the knob. How would you translate the instructions in degrees to radians?A a -> Two water Separated from A ond B motors are Points at the Some time. Tw o what is the shortest distonce betwe en the bot ?CASE STUDY In Example 34.6 (page 1111), we imagined equipping 1950DA, an asteroid on a collision course with the Earth, with a solar sail in hopes of ejecting it from the solar system. We found that the enormous size required for the solar sail makes the plan impossible at this time. Of course, there is no need to eject such an object from the solar system: we only need to change the orbit. A much more pressing problem is Apophis, a 300-m asteroid that may be on a collision course with the Earth and is due to come by on April 13, 2029. It is unlikely to hit the Earth on that pass, but it will return again in 2036. If Apophis passes through a 600-m keyhole on its 2029 pass, it is expected to hit the Earth in 2036. causing great damage. There are plans to deflect Apophis when it comes by in 2029. For example, we could hit it with a 10- to 150-kg impactor accelerated by a solar sail. The impactor is launched from the Earth to start orbiting the Sun in the same direction as the Earth and Apophis. The idea is to use a solar sail to accelerate the impactor so that it reverses direction and collides head-on with Apophis at 8090 km/s and thereby keeps Apophis out of the keyhole. Consider the momentum in the impactors orbit (Fig. P34.75) when the solar sail makes an angle of = 60 with the tangent to its orbit. Current solar sails may be about 40 m on a side, but the hope is to construct some that are about 160 m on a side. Estimate the impactors tangential acceleration when it is about 1 AU from the Sun. Keep in mind that the sail is neither a perfect absorber nor a perfect reflector, and a heavier impactor would presumably be equipped with a larger sail. Dont be surprised by what may seem like a very small acceleration. FIGURE P34.75
- pps32 please dont copy existing answers or i will dislike your answer thanksThe switch in Fig. Q2 has been in position a for a long time. At t = 0 it moves to position b. Calculate i(t) for all t> 0. a t=0 6Ω 30 V 12 V 3 Q 2 F Fig. Q206 A charged particle (9 = 2C, m = 2kg) moves in a magnetic field B = Boz, Where Bo = 27. There is no electric field. It circlar path. to Imo moves in NO r(t) = r cos (wt) x + rsin (cut)^ If the total energy is 2J, what is the angular velocity w and radius r?
- A:17 A exam.ptuk.edu.ps على فيزياء عامه 2 نظري طولكرم Question 21 Not yet answered Marked out of 2.00 P Flag question A wire of variable cross-section is given below. The relation between the drift speeds on the two cross-sections 1 and 2 is Select one: a. V12=2Vd1 b. 9V42=Vd1 c. Va2=Va1 d. 3V42=2Vd1 e. 3V12=Vd1 Previous page Next page الامتحان النصفي Jump to... Return to: General )1. A 11.8 ?F capacitor is charged by a 25.0 V battery through a resistance R. The capacitor reaches a potential difference of 4.00 V at a time 3.00 s after charging begins. Find R. ________ kΩ 2.A proton moves perpendicular to a uniform magnetic field at a speed of 1.20 107 m/s and experiences an acceleration of 1.40 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. magnitude _______ PLEASE ANSWER BOTHCould you provide a diagram and explanation of why the arctan of Ac/At gives the direction of the acceleration vector? I'd like to understand. I'm assuming that the angle is in reference to the axis of the radius. Thank you.
- The figure below shows a conducting rod sliding along a pair of conducting rails. The conducting rails have an angle of inclination of θ=30 degrees. There is a resistor at the top of the ramp that connects the two conducting rails R=2.3Ω. The mass of the rod is 0.42 kg. The rod starts from rest at the top of the ramp at time t=0. The rails have negligible resistance and friction, and are separated by a distance L=15.7 m. There is a constant, vertically directed magnetic field of magnitude B=1.5 T. Find the emf induced in the rod as a function of its velocity down the rails. What is the emf when the velocity is 5.696E−03 m/s? .116 W What is the rod's terminal speed? 0.01138 m/s WHAT I NEED HELP WITH: A) When the rod moves at its terminal speed, what is the power dissipated in the resistor? For this I was using the equation P = V2/R and I got .00586 W which is wrong. What am I doing wrong?From the figure below, the differential length dl from point A to E is dxay F ax True False 22 A 2 E 1 1 H dy B с dx dz GThe figure below shows a conducting rod sliding along a pair of conducting rails. The conducting rails have an angle of inclination of θ=30 degrees. There is a resistor at the top of the ramp that connects the two conducting rails R=2.3Ω. The mass of the rod is 0.42 kg. The rod starts from rest at the top of the ramp at time t=0. The rails have negligible resistance and friction, and are separated by a distance L=15.7 m. There is a constant, vertically directed magnetic field of magnitude B=1.5 T. A) Find the emf induced in the rod as a function of its velocity down the rails. What is the emf when the velocity is 5.696E−03 m/s? B) What is the rod's terminal speed? C) When the rod moves at its terminal speed, what is the power dissipated in the resistor?