Show that the 238U isotope cannot spontaneously emit a protonby analyzing the hypothetical process                                     238/92U → 237/91Pa + 1/1HNote: The 237Pa isotope has a mass of 237.051 144 u.

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Chapter2: Relativity Ii
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Show that the 238U isotope cannot spontaneously emit a proton
by analyzing the hypothetical process
                                     238/92U → 237/91Pa + 1/1H
Note: The 237Pa isotope has a mass of 237.051 144 u.

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If the given uranium spontaneously emits a proton, the decay process will be,

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