   Chapter 7, Problem 5P

Chapter
Section
Textbook Problem

A dentist’s drill starts from rest. After 3.20 s of constant angular acceleration, it turns at a rate of 2.51 × 104 rev/min. (a) Find the drill’s angular acceleration. (b) Determine the angle (in radians) through which the drill rotates during this period.

(a)

To determine
The angular acceleration of the doctor’s drilling.

Explanation

Given info: The initial angular velocity is 0rev/min , the final angular velocity is 2.51×104rev/min , and the time interval is 3.20s .

Explanation:

The formula for the angular acceleration of the drilling is,

α=ωfωiΔt

• α is the angular acceleration of the drilling.
• ωi is the initial angular velocity.
• ωf is the final angular velocity.
• Δt is the time interval.

Substitute 0rev/min for ωi , 2.51×104rev/min for ωf , and 3

(b)

To determine
The angle through which the drill rotates during the period.

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