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For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be produced by the complete conversion of 0.50 mole of the reactant indicated in boldface. State clearly the mole ratio used for each conversion. msp; NH 3 ( g ) + HCl ( g ) → NH 4 Cl ( s ) msp; CH 4 ( g ) + 4 S ( s ) → CS 2 ( l ) + 2 H 2 S ( g ) msp; PCl 3 ( l ) + 3 H 2 O ( l ) → H 3 PO 3 ( a q ) + 3 HCl ( a q ) msp; NaOH ( s ) + CO 2 ( g ) → NaHCO 3 ( s )

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

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Chapter
Section
BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
Chapter 9, Problem 14QAP
Textbook Problem
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For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be produced by the complete conversion of 0.50 mole of the reactant indicated in boldface. State clearly the mole ratio used for each conversion.

msp;  NH 3 ( g ) + HCl ( g ) NH 4 Cl ( s )

msp;  CH 4 ( g ) + 4 S ( s ) CS 2 ( l ) + 2 H 2 S ( g )

msp;  PCl 3 ( l ) + 3 H 2 O ( l ) H 3 PO 3 ( a q ) + 3 HCl ( a q )

msp;  NaOH ( s ) + CO 2 ( g ) NaHCO 3 ( s )

Interpretation Introduction

(a)

Interpretation:

Number of moles and grams of the product(s) would be produced by complete reaction of 0.50 mole of the reactant indicated in boldface in the given balanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

Explanation of Solution

According to the balanced equation, mole ratio between NH3 ( g ) and NH4 Cl( s ) = 1 mol NH4Cl(s)1 mol NH3 (g)

So, Amount of NH4 Cl( s ) produced = 0.50 mol NH3 (g)×

1 mol NH4Cl(s)1 mol NH3 (g)

= 0

Interpretation Introduction

(b)

Interpretation:

Number of moles and grams of the product(s) would be produced by complete reaction of 0.50 mole of the reactant indicated in boldface in the given balanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

Interpretation Introduction

(c)

Interpretation:

Number of moles and grams of the product(s) would be produced by complete reaction of 0.50 mole of the reactant indicated in boldface in the given balanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

Interpretation Introduction

(d)

Interpretation:

Number of moles and grams of the product(s) would be produced by complete reaction of 0.50 mole of the reactant indicated in boldface in the given balanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

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Chapter 9 Solutions

Introductory Chemistry: A Foundation
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