5) Isopentyl acetate (aka banana oil) can be prepared by an esterification reaction using acetic acid and isopentyl alcohol. The balanced reaction is shown below. If a student reacts 5.50 mL of acetic acid with 2.35 mL of isopentyl alcohol and obtains 3.25 mL of isopentyl acetate as the product, what was the percent yield of the reaction? H* + H20 HO, HO, acetic acid isopentyl alcohol isopentyl acetate bp 142 °C bp 118 °C bp 129 °C MW 60.0 MW 88.2 MW 130.2 d. 1.05 g/mL d. 0.810 g/mL d. 0.867 g/mL

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Chapter3: Stoichiometry
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Problem 7RQ: Consider the hypothetical reaction between A2 and AB pictured below. What is the balanced equation?...
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5) Isopentyl acetate (aka banana oil) can be prepared by an esterification reaction using acetic acid
and isopentyl alcohol. The balanced reaction is shown below. If a student reacts 5.50 mL of acetic
acid with 2.35 mL of isopentyl alcohol and obtains 3.25 mL of isopentyl acetate as the product,
what was the percent yield of the reaction?
H*
+
H20
HO,
HO,
acetic acid
isopentyl alcohol
isopentyl acetate
bp 142 °C
bp 118 °C
bp 129 °C
MW 60.0
MW 88.2
MW 130.2
d. 1.05 g/mL
d. 0.810 g/mL
d. 0.867 g/mL
Transcribed Image Text:5) Isopentyl acetate (aka banana oil) can be prepared by an esterification reaction using acetic acid and isopentyl alcohol. The balanced reaction is shown below. If a student reacts 5.50 mL of acetic acid with 2.35 mL of isopentyl alcohol and obtains 3.25 mL of isopentyl acetate as the product, what was the percent yield of the reaction? H* + H20 HO, HO, acetic acid isopentyl alcohol isopentyl acetate bp 142 °C bp 118 °C bp 129 °C MW 60.0 MW 88.2 MW 130.2 d. 1.05 g/mL d. 0.810 g/mL d. 0.867 g/mL
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