When the sugar glucose, C 6 H 12 O 6 , is burned in air, carbon dioxide and water vapor are produced. Write the balanced chemical equation for this process, and calculate the theoretical yield of carbon dioxide when 1.00 g of glucose is burned completely.

Interpretation:

To write the balance combustion reaction of complete combustion of glucose and to calculate the theoretical yield of carbon dioxide when 1.00 g of glucose is burned completely.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

In combustion reaction organic compounds burn in presence of oxygen or air and produce water and carbon dioxide with energy. It is an exothermic reaction. In this reaction, carbon is oxidized by addition of oxygen to carbon dioxide.

For example the combustion reaction of ethane is following:

2 C2H6(g) + 7 O2(g)→Δ4 CO2(g) + 6 H2O(g)              Reactants                         Products             

The general reaction of combustion as follows:

Organic compound + O2(g) →Δ CO2 (g) + H2O (l)+energy

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles = mass in gmolar mass.

Theoretical yield is also known as calculated yield. Theoretical yield is the amount of product which is theatrically calculates by the amount of limiting agent. It is the maximum amount of product which is formed in any reaction.

Other name of actual yield is observed yield. The actual yield for a reaction may be less than the theoretical yield.

The percentage yield is calculated by the actual or observed experimental yield divided by the theoretical yield and multiplied by 100.

The percentage yield can be calculates by the use of following expression:

Actual yield or given yield Theoretical yield or calculated yield ×100%   

Theoretical yield is the greatest amount of a product possible from a reaction, when assume that the reaction goes to 100% competition.

The balance combustion reaction of complete combustion of glucose is as follows:

C6H12O6(s) + 6O2(g)→Δ6 CO2(g) + 6 H2O(g)              Reactants                         Products 

First calculate the mole of glucose as follows:

Number of moles = amount in gmolar massNumber of moles = 1.00 g C6H12O6180.156 g mol−1 C6H12O6                            =0