# Advanced Computer Networking Home Work

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CSC 535-02 Advanced Computer Networking Home Work - 4 1) A signal has a fundamental frequency of 1000 Hz. What is its period? - Given, Fundamental Frequency (f) = 1000Hz Period (P) = 1/f =1/1000 = 0.001 Sec =1 millisecond 2) If the solid curve in Figure 1 represents sin (2πt), what does the dotted curve represent? That is, the dotted curve can be written in the form A sin (2πt + φ); what are A, f, φ? - For a given blue Solid Curve given equation is = sin (2πt) For a Dotted Curve: Phase Angle φ = 0 At time t=0, Amplitude (A) = 2V Time t = 0.5 Frequency (f) = 1/t = 1/0.5 = 2 Hz Therefore equation for Dotted Curve is = 2sin (2π*2*t+0) =2sin (4π*t) 3) Given the following frequencies listed below, calculate the corresponding periods: (a) 24Hz (ﬁnd T in ms) - Given frequency f=24Hz Frequency (f) = 1/time period f = 1/T T = 1/f = 1/24 = 0.04167 seconds = 41.67 ms (b) 8MHz (ﬁnd T in micro seconds) - Here, frequency f =8MHz = 8 *106 Hz T = 1/f = 1/8*106 Hz = 0.125*10-6 sec = 0.125 micro seconds (c) 140 kHz (ﬁnd T in micro seconds) - Here, frequency f= 140 KHz f = 140 * 103 Hz f = 140 * 103 *103 /103 = 140* 106/1000 =0.14 * 106 T = 1/f