The study performed on students enrolled in the MBA program at Whatsamattu U will determine the mean of students GPA. The variables in this study include their age, gender, major; GPA, Bachelors GPA, course load, English speaking status, family, and weekly hours spent studying. Although it is common, most schools grades at the MBA level are divided only between A's and B's. For that reason, the graph displays an expected mean GPA of 3.50. In order to examine the unknown data, we will conduct a hypothesis test with significance level of 0.50 (a tolerance level of error we are willing to accept during this study). Furthermore, the one sample hypothesis test for the mean will calculate the unidentified statistics to determine if the …show more content…
Statistic supporters report that if a null rejection transpires, then the null hypothesis must conclude that H1 is true (Mirabella, 2011). Following, the upper-tail test identifies a p-value of 0.9998, which suggest not rejecting the null hypothesis. Research contest the p-value is the possibility of making a mistake if the null is rejected (Farnsworth, 2016). Nevertheless, if a rejection of the null hypothesis occurs, then insufficient evidence proposes that H1 exists as proofs (Mirabella, 2011). Further concluding the lower-tail test identifies a p-value of 0.002, therefore, the decision remains; reject the null hypothesis. According to Mirabella (2011), the confidence interval is another way to acquire the sample mean. To organize this, just utilize the mean added to or minus a margin of error. Furthermore, the margin of error or sampling error is merely the difference between the results and the truth (Mirabella, 2011). Therefore, the sampling error necessity determined is vital in order to develop a sample mean. Early units have taught us, the Z score times the standard deviation divided by the square root of the sample size. Therefore, the Z score remains known as plus/minus of the level of confidence based on the data in the normal distribution. Through reflection, the standard deviation remains characterized as a typical distance of an observation from the distribution center or middle value (Barde & Barde, 2012). Following,
So, we should reject the null hypothesis H0. At a 0.05 level of significance level, we conclude that there is a significant difference between the average height for females and the average height for the males.
While in high school my GPA was below a 2.0 and that was because I was involved in many sports that I had a strong passion for. I was very driven and dedicated, that most of my free time went into trying to be the best on the softball field and on the wrestling mat in hopes of receiving a scholarship. As an athlete you only needed a 2.0 GPA to compete and at that time I did not focus too much on exceeding that standard.
Because the p-value of .035 is less than the significance level of .05, I will reject the null hypothesis at 5% level.
Testing allows the p-value that represents the probability showing that results are unlikely to occur by chance. A p-value of 5% or lower is statistically significant. The p value helps in minimizing Type I or Type II errors in the dataset that can often occur when the p value is more than the significance level. The p value can help in stopping the positive and negative correlation between the dataset to reject the null hypothesis and to determine if there is statistical significance in the hypothesis. Understanding the p value is very important in helping researchers to determine the significance of the effect of their experiment and variables for other researchers
How can it be that a student’s ACT score is more important than their GPA? Is it possible that a four-hour test can hold more weight than four years of high school grades? Would it not be great if students could get the same amount of money for a high GPA that they can get for a high ACT score? GPA can show hard work, strength, self-discipline, consistency, intelligence and personal accomplishments. Scholarships should not be awarded based primarily on ACT scores but on a student’s GPA. Scholarships should be awarded for keeping a high grade point average throughout high school. It is just as difficult or more to keep high grades throughout four years of high school as it is to go take four-hour test and achieve a high score.
hypothesis is rejected (Salkind, 2014). The critical value is also used to calculate the margin of error (Salkind, 2014). Lastly, the critical value is determined from the alpha or significance value of the hypothesis test (Salkind, 2014).
Null hypothesis. The null hypothesis, denoted by H0, is usually the hypothesis that sample observations result purely from chance. In this case, according to null hypothesis there is no significant difference between business students at Rocky University who were involved in cheating and business students elsewhere.
Consider the following scenario in answering questions 5 through 7. In an article appearing in Today’s Health a writer states that the average number of calories in a serving of popcorn is 75. To determine if the average number of calories in a serving of popcorn is different from 75, a nutritionist selected a random sample of 20 servings of popcorn and computed the sample mean number of calories per serving to be 78 with a sample standard deviation of 7.
Since the P-value (0.386) is greater than the significance level (0.05), we fail to reject the null hypothesis. The p-value implies the probability of rejecting a true null hypothesis.
GPPA program provides me a guarantee admission for my future education in Nursing. As a GPPA member, I will keep my GPA above average during college years, and do my best to make a steady progress academically. Nurse anesthetist is my dream career, I would like to take the risks and complete any recommended courses to pursue my goals. becoming a member of GPPA program will offer me a considerable opportunity to complete my Bachelor's degree in Nursing and helps me achieve my goal with higher level educational content.
To test the null hypothesis, if the P-Value of the test is less than 0.05 I will reject the null hypothesis.
“Hypothesis testing is a decision-making process for evaluating claims about a population” (Bluman, 2013, p. 398). This process is used to determine if you will accept or reject the hypothesis. The claim is that the bottles contain less than 16 ounces. The null hypothesis is the soda bottles contain 16 ounces. The alternative hypothesis is the bottles contain less than 16 ounces. The significance level will be 0.05. The test method to be used is a t-score. The test statistic is calculated to be -11.24666539 and the P-value is 1.0. The P-value is the probability of observing a sample statistic as extreme as the test statistic, assuming the null hypothesis is true. The T Crit value is 1.69912702. The calculations show there is enough evidence to support the claim that the soda bottles do
Conclusion : Fails to reject the null hypothesis. The sample does not provide enough evidence to support the claim that mean is significantly different from 12 .
If someone asked me where I am going to be in ten years, this would be my answer. I will have a great, high-paying job, and beautiful wife and family, and a nice sports car parked in front of my lovely house. When I look into the future, I see myself being successful and happy. Even though I always pictured myself this way, I never worried too much about how I would get there. I feel the Suffolk University can lay the groundwork for making these dreams into reality.
The null hypothesis suggests that there is no difference between the means of the three samples, while the claim in the alternative hypothesis suggests that at least one mean is different.