| Cleaning Time | Waxing time | C1 | 9 | 6 | C2 | 6 | 2 | C3 | 5 | 7 | C4 | 3 | 5 | C5 | 8 | 4 | 41. (7 points) An automobile detailing shop has the following jobs waiting to be processed. All jobs (cars requiring detailing) must first be cleaned, then waxed. a. What processing sequence will minimize the makespan for these jobs? Job | Cleaning Time time | Cleaning Time end time | Waxing time time | Waxing time end time | Waxing time idle time | C4 | 3 | 3 | 5 | 8 | 3 | C3 | 5 | 8 | 7 | 15 | 0 | C1 | 9 | 17 | 6 | 23 | 2 | C5 | 8 | 25 | 4 | 29 | 2 | C2 | 6 | 31 | 2 | 33 | 2 | b. What is the minimum makespan for this set of five jobs? Makespan is 33 (POM SW output is attaced in excel) 42. (10 points) …show more content…
Sample Mean Range Sample | Mean | Range | 1 | 7.2 | 0.7 | 2 | 7.6 | 1 | 3 | 7.1 | 1.4 | 4 | 7.8 | 1.1 | 5 | 7.8 | 0.6 | 6 | 7.5 | 1.2 | _ a. Calculate the 3 X-chart and R-chart control limits. X bar = Average (Mean) = (7.2+7.6+7.1+7.8+7.8+7.5) / 6 = 7.50 Avge Range R bar = Avge (Range) = (0.7+1+1.4+1.1+0.6+1.2) / 6 = 1.00 Using Constant Table, we find the value of A2 for Subgroup of n=6 as A2 = 0.483 Now Upper control Limit UCL(X) = X + A2*R = 7.50+0.483*1 = 7.983 & Lower control Limit LCL(X) = X - A2*R = 7.50 - 0.483*1 = 7.017 Now we calculate the Upper Control Limit for Range. Recall that when n <7, LCL( R) = 0. Here n=6. So LCL(R) =0 & UCL (R ) = D4*R Looking up Contant Table, we find for n=6, D4 = 2.282 So UCL (R ) = D4*R = 2.282*1 = 2.282 b. Calculate the mean (X) and range (R) for the following sample, which was taken from the same process at a later time. Item number: 1 2 3 4 5 Weight: 7.5 8.0 8.2 7.5 7.4 Mean (X) = Avge(Weights) = (7.5+8.0+8.2+7.5+7.4) / 5 = 7.72 Range (X) = Highest Value of Weight – Lowest value of weight = 8.2-7.4 = 0.8 Based on this sample and the control chart limits that you calculated in part (a), is the process in control? Why or why not? Based on X & R UCL & LCL found in (a ), we can say that Process is in Control. This is because, all Mean of samples
A process that monitors standards by take measurements and corrective action as needed. It is in control when only variation is natural, if variation is assignable then discover cause eliminate it. Take samples to inspect/ measure- reduce inspection time, reduce opportunity of bad quality. Control charts graph of process data over time-show natural and assignable causes. Control charts for variable data (characteristic that is measured, length,height, etc) are X-chart (average) and R-chart (range)must use x and r to get correct results. central limit theorem follow normal curve. When we know . When we don’t know . Control charts for attributes (categorical-defective, good/bad) P-chart (percent) or C-chart
than results controls. The analysis of this system leads to insights about some of the factors that
The given chart provides data about the percentage of personnel's contenment in college A, B, C and D from 1991 to 2002. Overall, there was a unpredictable raise in the figure of college C which changed from the lowest to highest position of the totall given information in the final phase.
Quality Associates, Inc., a consulting firm advises its clients about sampling and statistical procedures that can be used to control their manufacturing processes. In one particular application a client gave Quality Associates a sample of 800 observations taken during a time in which the client’s process was operating satisfactorily. The sample standard deviation of this data was 0.21; hence with so much data, the population standard deviation was assumed to be 0.21. Quality Associates then suggested that random samples of size 30 be taken periodically to monitor the process on an ongoing basis. By analyzing the new samples, the client could quickly learn whether the process was operating satisfactorily. When the process was not operating satisfactorily, corrective action could be taken to eliminate the problem. The design specification indicated the mean for the process should be 12. The hypothesis test suggested by Quality Associates follows.
b) No, because it shows that the change is a negative change in poverty, which means it, is not the smallest change. To find this sort data table to acceding data in order to find the lowest percent change being 0%.
The highest target given to the stock is $20 and the lowest target is $15. They expect the variance to be within $1.69 of the average price.
* Introduces the construction and use of statistical process control (SPC) charts and an understanding of the relationship between SPC and conformance quality.
Statistical Process Control (SPC) is a method of controlling the quality of a manufacturing process and is most often affiliated with control charts. However, SPC in reality is a group of tools and includes additional statistical and evaluation/measurement methods. Smith, Megahed, Jones‐Farmer and Clark defined seven basic tools of SPC including; histograms, check sheets, Pareto charts, cause-and-effect diagrams, defect concentration diagrams, scatter diagrams and of course the aforementioned control charts (2014). These tools represent the scope and overall purpose/pursuit of SPC which is; “any statistical method designed to detect changes in a process over time” (Woodall & Montgomery, 1999, p. 377). Since control charts is often the most discussed of these seven tools; it is important to note there are many different types of control charts. The main control charts include; process charts which are R-charts and s-charts, non-conforming item charts also known as p-charts and np-charts and finally average numbers of non-conformity charts or c-charts and u-charts (Woodall & Montgomery, 1999).
3. The level of inventory at which a new order should be placed is known as the
Given that SCC Management would like to observe statistical process control performed for each of the shifts with 3σ standards, we have developed X ̅ and R Charts for each shift. The R-Control chart demonstrates that process variability during both shifts is in control as observed in figures 1 and 2; none of the sample ranges fall outside of the control limits. However, there is a difference in patterns for the R-chart between these two shifts.
2. A distribution of 6 scores has a median of 21. If the highest score
E) A 5th worker is hired. What is the capacity of the line now? 1/70 or 0.0143 unit per second (0.858 unit per minute)
Statistical process control refers to a statistical method used to separate variation produced b y special causes and varation produced by natural causes. This is done so that it is possible to eliminate the special causes and to establish and maintain consistency in the process, allowing the process to be improved.
Operations administration concentrates on precisely dealing with the procedures to create and circulate items and administrations. Operations administration is the procedure, which joins and changes different assets utilized as a part of the creation/operations subsystem of the association into quality included item/benefits in a controlled way according to the arrangements of the association. In this way, it is that part of an association, which is worried with the change of a scope of inputs into the required (items/administrations) having the essential quality level.
Controlled- The controlled variable will be the thirty plants that are given excess carbon dioxide.