Introduction For this experiment, we are going to determine the effect of temperature on solubility, to be done in a chemical by dissolving a solute in a definite amount of solution which is saturated. Specifically, the goal of this experiment is to prepare a saturated solution of Na2C2O4 in water at different temperatures, determine the effect of temperature in solubility, and to apply Le Chatelier's Principle. We can do all this by simply titrating a certain amount of standard KMnO4, and measuring how much KMnO4 was needed to help Na2C2O4 reach chemical equilibrium at certain temperatures. In doing this, we will have fulfilled all the goals of our experiment, as well as being able to determine the Solubility of Na2C2O3 at both 20 and …show more content…
I then added 50 ml of distilled to the test tubes A1, B1, C1 and D1, then titrated them with the potassium permanganate solution (making sure to add 15 ml 3M sulfuric acid in each), then recorded the amount it took for them to turn pink.
Data
A. Standardization of KMnO4 solution:
Sample g Na2C2O4 moles Na2C2O4 (x 10^-3) moles KMnO4 (x 10^-3) ml KMnO4 used M KMnO4
#1 .47 3.51 1.4 15.5 .090
#2 .50 3.73 1.5 16 .093
Average M = .091
B. Solubility of Na2C2O4 at different temperatures: in M and g/ L.
Sample and temp (C): ml of KMnO4 titrated moles KMnO4 (x 10^-4) moles NaC2O4 dissolved (x 10^-3) M (moles/L) Na2C2O4 g Na2C2O4 dissolved in sample g / L Na2C2O4
A1 3 5.0 4.55 1.14 .228 .152 30.5
B1 31.1 6.0 5.46 1.37 .274 .183 36.6
C1 45 8.8 8.01 2.00 .400 .268 53.7
D1 - 80 9.5 8.65 2.16 .432 .290 57.9
Solubility of Na2C2O4 in g / L Experimental Value in g / L Handbook Value in g / L
At 20 C 36 37
At 100 C 73 63.3
C. Relationship of K and ∆H
Sample Average M of Na2C2O4 K=[Na^+]^2[C2O4] ln K T K 1 / T K (x 10^-3)
A1 .228 .047 -3.05 276 3.62
B1 .274 .082 -2.50 304.1 3.29
C1 .400 .256 -1.36 318 3.14
D1 .432 .322 -1.13 353 2.83
At 20 C .276 .084 -2.48 293 3.41
At 100 C .472 .421
At five minute intervals over the next fifteen minute period, record the color intensity of the solution of each test tube.
The null hypothesis will be that the test tubes with an increase in temperature, pH values, enzyme concentrations, and substrate concentration will have a very small color change or no color change at all. The alternate hypothesis is that the test tubes containing an increase in temperature, pH values, enzyme concentrations, and substrate concentration will all have an intense color change; the more the change, the more intense the color change will be.
Temperature is known as one of the factors that affect the solubility of a gas in its solvent. Because the enthalpy of solution for gases dissolved in waters is usually
The procedures for experiment A, B, and C all start the same. The first step is to put on goggles and get the data collection device set properly. The labquest needs to be plugged into the colorimeter accurately so that a click is heard when putting it in. The labquest needs to be reading digitally and the colorimeter needs to be set to 635 nm. Then shake the chloroplast solution and take a clean cuvette and fill it with 3 mL of distilled water, 3 drops of the chloroplast solution, and cap it. This is used as a blank to calibrate your labquest. Double check that the labquest is reading absorbance, this assures that the colorimeter is plugged into the labquest accurately. Insert the blank into the colorimeter and hit the calibration button. Take out the blank and empty it. The labquest is now set to experiment with. Make sure that the heat bank is set in front of the lamp and that the lamp is on. The cuvette must be placed on the opposite side of the heat bank in the path of light in the box so that no other light can interfere with the experiment.
After carefully taking them out, observe each test tubes color and then fill Table 2 with the results.
4. We observed the test tubes and compared the colors produced from the reaction to the color palette in 1 minute intervals for 5 minutes total.
AP Chemistry Background The solubility product constant, Ksp, is a particular type of equilibrium constant. The equilibrium is formed when an ionic solid dissolves in water to form a saturated solution. The equilibrium exists between the aqueous ions and the undissolved solid. A saturated solution contains the maximum concentration of ions of the substance that can dissolve at the solutions temperature. A knowledge of the Ksp of a salt is useful, since it allows us to determine the concentration of ions of the compound in a saturated solution. This allows us to control a solution so that precipitation of a compound will not occur, or to find the concentration needed to cause a precipitate to form. The solubility product which will be
As the temperature of water increases, the particles of solid Potassium chloride, KCl, which are absorbing energy from its surrounding, start moving more easily between the solution and its solid state because. According to the second law of thermodynamics, the particles will shift to the more disordered, more highly dispersed solution state. I predict that as the temperature of a KCl and water mixture increases, then the solubility of the KCl will also increase.
· I set up the apparatus as shown in the diagram. I then placed a
Solute – A solute is the material (solid, liquid or gas) that is dissolved in the solvent to create the solution.
Add 4 drops of phenolphthalein in to the prepared acetic acid, and check whether the color changes to dark pink.
Remove the tubes and add 2-3 drops of Iodine – potassium – iodide solution to each tube.
After the 30 minutes, the color was observed and recorded on the data sheet. The dialysis tubing was removed from the beaker and a small slice was made, we then used a glucose indicator strip to test for the presence of glucose, along with the solution in the beaker. The results were then recorded in table 1on the data sheet.
Half of each tube’s contents are poured into a new test tube each respectively after the tubes are incubated for 1 hour. One set of tubes is tested for:
During the Benedict's test, the contents of tube B did not change, indicating the absence of sugar in that particular substance. However, the contents of tube A did change orange indicating the presence of sugar in that substance. During the Lugol's test, the content of tube A did not change dark purple indicating the absence of starch in that substance However, the content of tube B changed to dark purple