Salt Solution Concentrations And Water On The Mass Of Potatoes

Figure 1: Percentage change in potato tuber mass vs. sucrose concentration. The percent change in mass decreased as the sucrose concentration increased. Relative osmotic concentration was measured as the percent change in mass of sucrose concentration over one hour.

Diffusion and osmosis, Diffusion and osmosis happens in everyones everyday way of living, this can include when you spray your deodorant before school in the bathroom to then find going into the next room your still chocking on the dry smell of the deodorant this is diffusion when the particles in the air move from one place to another. Other example is when you go to have a bath, you fill the water put a bath bomb in the water and go get your towel and clothes when you get the bath bomb is gone but some little piece may be left over this is Osmosis this happens when two different concentrated solutions are separated then the solvent will then diffuse by the membrane from the less concentrated solution over to the more concentrated solution,

Michelle Lui Period 7 AP Bio Lab partners: Ashwin Sannecy, Matthew Kim An Investigation Of The Effect Of Different Concentrations of Sucrose On Osmosis Research Question: Part A: How does the molarity of sucrose solution inside dialysis tubes affect the percent change in mass of the tube after 20 minutes? Part B: How will the molarity

Discussion Though the theory following the hypothesis is correct and the experiment was carried out with as much attention as possible in a high school laboratory, the results obtained were still indicative of a few errors and did not support the predicted hypothesis. From the results obtained it can be concluded that as the concentration of sucrose increases the average percentage change in mass decreases. This is because the salt concentration inside the potato cubes of 10%, 15% and 20% concentration is less that in the salt concentration on the sucrose solution, thus the three cubes submerged in the 10% - 20% concentrated solution lost mass (hypertonic). However the cube submerged

in mass after the process of osmosis. Materials and Equipment: Refer to Biology 12 Lab Manual – Investigation 13 Procedure: Refer to Biology 12 Lab Manual – Investigation 13 Data and Observations: The Potatoes change in mass after the process of Osmosis Test Tube # | Concentration of Sucrose Solution (mol/L) | Initial mass (g) | Final mass (g) | Change in mass (g) | Percentage change in mass (%) | 1 | 1.0 | 5.12 | 3.63 | -1.49 | 29.0% | 2 | As the Concentration of the Sucrose Solution decreases, the more the potato’s mass increases. This is due to the solution being hypertonic. So, as the solute concentration gets lower, the potato’s water concentration will get higher, therefore more water particles from the solution will absorbed by the potato. Some changed very little in mass because the concentrations of the H2O molecules in the potato and outside the potato were equal. This equality in concentration is called Isotonic.

Prediction/Hypothesis: My prediction is that as the concentration increases, the potato cell will lose more weight. This is because of the osmosis of water particles from the potato cell cytoplasm to the solution, resulting in a loss of weight. As the concentration decreases, the potato will lose less weight until a certain point where the osmosis of particles in and out of the potato cells will be equal. I also predict that as the salt

Results and Observations Test Tube # | Solute Concentration (mol/L-1) | Initial MassI (g) | Final MassF (g) | Change in Mass(F – I) (g) | Percent Change in Mass(F – I) × 100 I | 1 | 0 | 1.3g | 1.6g | 0.3g | 23.08% | 2 | 0.2 | 1.1g | 1.1g | 0.0g | 0.00% | 3 | 0.4 | 1.2g | 1.0g | - 0.2g | - 16.67% | 4 | 0.6 | 1.5g | 1.2g | - 0.3g | - 20.00% | 5 | 0.8 | 1.5g | 1.1g | - 0.4g | - 26.67% | 6 | 1.0 | 1.6g | 1.3g | - 0.3g | - 18.75% | Figure 1.2: Data Table of Results After 24H in Solute Concentration Figure 1.2: Data Table of Results After 24H in Solute Concentration Figure 1.3: Graph of Results After 24H in Solute Concentration Figure 1.3: Graph of Results After 24H in Solute Concentration As we can see in Figure’s 1.2 and 1.3, when there was no sucrose solution, the potato increased in weight. This is due to the fact that the sucrose solution was hypertonic in comparison to the potato slice. Through osmosis, the solution moved along the concentration gradient and into the potato slice making it hypotonic. When there were higher concentrations of sucrose solution, the potato decreased in weight. This is due to the fact that the potato was hypertonic in comparison to the potato. Through osmosis, sucrose from the potato moved along the concentration gradient out and into

[Type text] [Type text] [Type text] _An experiment on the effect of surface area to volume ratio on the rate of osmosis of Solanum tuberosum L._

Hypothesis: I think that the potato will absorb more starch than the sweet potato and they will both absorb relatively similar amounts of water.

Materials • Potato (four slices) • Knife • Beaker (4) • Salt Solution .2, .4, .6 mol • Distilled water • Food Scale • Paper Towels Methods First I gather all my materials needed for the experiment (see materials list). Second I peel and slice potatoes weigh each potato in grams. Get these slices to weigh the same in mass because if they vary to much in mass that could affect the results of the experiment. Third I place each potato in its own beaker. Fourth once the potatoes are placed in beakers I make sure to place enough solution to fully cover the potato. Each beaker should have a different amount of

Diffusion and Osmosis in Potato Cores By Brittany Pangilinan Abstract Van’t Hoff’s Law suggests that the osmotic potential of a cell is proportional to the concentration of solute particles in a solution. The purpose of this experiment was to determine if there are any differences between the osmolalities, the no-weight-changes of osmolalities, and the water potentials of potato cores in different solutions of different solutes. The percent weight change of the potato cores was calculated through a “change in weight” method. The potato core’s weight was measured before and after they were put into different concentrations of a solute for 1.5 hours. In our experiment, there were no significant differences from the osmotic potentials of our results and the osmotic potentials of other scientists work. Ending with chi square values of 2.17 and 2.71, and p values of 0.256 and 0.337, concluding that there is no difference in water potentials of potato cores in different solutions of different solutes at varying concentrations.

Showing an example of diffusion with the water molecules equally back and forth the semi-permeable membrane of the potatoes and the saucer of water. The hypertonic solution of salt water has given an example of osmosis. The water molecules passed through the semi-permeable membrane out of the potatoes but weren’t able to get back in as easily due to the salt blocking the membranes passage. This left the potatoes in the salt water saucer feeling flexible and spongy almost leaving the potato a little

Chloé ten Brink Biology Block C Dr Reza 22/11/2017 Bio Lab Report An Experimental Study on the Estimation of the Osmolarity of Potato Cores Research Question: How do different concentrations of sucrose solutions (0M, 0.2M, 0.4M, 0.6M, 0.8M, 1M) affect the mass of potato cores when in sucrose solution?

Next Page (didn't fit) Concentration (M)0m.2m.4m.6m.8m1m Initial Mass(g)3.6g3.8g3.9g3.1g3.0g3.0g Final Mass (g)4.1g3.9g3.4g2.2g2.0g1.9g % Change in Mass14.9%1.8%-12.1%-28.6%-33.3%-36.9% Analysis: The Graphs below show the percent changes in mass for both the class averages and our group's averages:

Introduction Osmosis is when water passes through a cell membrane, it is also form of a diffusion, which is a form of passive transport. Osmosis will continue to until an equilibrium is reached which is when the solutions are isotonic. This means that the solution has the same amount of solute on both sides. If the solution is hypertonic, it has more solute in the solution. In this situation water will move towards it. if the solution is hypotonic, it has less solute in the solution. Whereas in this situation, water will move out of the solution.