-). A new procedure for determining cholesterol in blood serum was used with a NIST standard sample producing the following results: 2.24, 2.21, 2.16, 2.21, and 2.19 mg/ml. If the NIST certified value is 2.12 mg/ml, determine if there a significant difference between the mean of the results and the certified or "true" value at the 95% confidence level?
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- An analysis of city drinking water for total hardness was done by two students in the laboratory and produced the following results (in ppm CaCO3): Student A: 228.3, 226.4, 226.9, 227.1, and 228.6. Student B: 229.5, 226.1, 230.7, 223.8, and 227.5What is the 95% confidence interval for the mean?A chemist working in a hospital clinical laboratory obtained the following values for uric acid in blood serum: 4.63, 4.58, 4.82, 4.31, 4.67 and 4.60 mg%. What value should be reported as the mean? Value of QT at 90 % confidence level is 0.56.A stock solution of 0.225 +/- 0.003 M NaNO2 was transferred to a 100 mL volumetric flask (class A) and diluted to the mark. If 7 mL of the stock solution was transferred using one 5-mL and two 1-mL volumetric pipettes, what is the new concentration of the solution and the uncertainty? Please show how to calculate the uncertainty, that is the one part I don't understand how to do
- A pipet is used to transfer 6.00 mLmL of a 3.75 MM stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2OH2O to the calibration mark. The solution is thoroughly mixed. Next, 10.00 mLmL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2OH2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”A second spectrophotometric method for the quantitative analysis of Pb2+ in blood yields an Ssamp of 0.712 for a 5.00 mL sample of blood. After spiking the blood sample with 5.00 μL of a 1560 ppb Pb2+ external standard, an Sspike of 1.546 is measured. What is the concentration of Pb2+ in the original sample of blood?Solve the required of the following and show the complete process to be able to gain the value of the correct answer. Given: Volume of Vinegar used (ml) = 25.00 mL Volume after dilution = 250.00 mL Volume of Aliquot used (ml) = 50.00 mL Volume NaOH used (ml) = 34.85 mL Concentration of NaOH = 0.09919475765 M Required: Calculate % (w/v) CH3COOH = ? P.S. Use weight in grams and volume of vinegar in mL, but correction based on aliquot should be made.
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- 1. Replicate analyses of the lead content in a blood sample gave the following results: 0.789, 0.781, 0.795, 0.792, and 0.784 ppm Pb. Calculate the mean, standard deviation, variance, relative standard deviation, and standard deviation of the mean of the data.4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.7. A procedure for measuring the amount of creatinine in blood was applied to a standard blood sample and the following results were produced: 0.787, 0.812, 0.796, 0.739, 0.802, and 0.823 mg/dL. a) Can any of the data points be rejected by the Grubbs test? b) What is the 95% confidence interval for the data?