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0.2 0.5×10-4 1x10-4 1.5x10-4 2x10-4 [Fe(SCN2+)]equ, (M) y = 4.26442 × 103 x + 0.0202852 R2 = 0.999902 In the laboratory you measured RMSE, however here you will enter the R2 value displayed on the graph. SLOPE, (M-1) INTERCEPT R2 Unrounded 4.26442 x 103 0.0202852 0.999902 Rounded 4.264 x 103 0.02029 0.9999 CALCULATED VALUE • The path length of the vial is 1.00 cm. Unrounded Rounded Molar absorption coefficient for Fe(SCN)²+, (M-1 cm-1) 3

0.2 0.5×10-4 1x10-4 1.5x10-4 2x10-4 [Fe(SCN2+)]equ, (M) y = 4.26442 × 103 x + 0.0202852 R2 = 0.999902 In the laboratory you measured RMSE, however here you will enter the R2 value displayed on the graph. SLOPE, (M-1) INTERCEPT R2 Unrounded 4.26442 x 103 0.0202852 0.999902 Rounded 4.264 x 103 0.02029 0.9999 CALCULATED VALUE • The path length of the vial is 1.00 cm. Unrounded Rounded Molar absorption coefficient for Fe(SCN)²+, (M-1 cm-1) 3

Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter10: Effect Of Electrolytes On Chemical Equilibria
Section: Chapter Questions
Problem 10.16QAP
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I need help calculating the molar absorption please!

0.2 0.5×10-4 1x10-4 1.5x10-4 2x10-4 [Fe(SCN2+)]equ, (M) y = 4.26442 × 103 x + 0.0202852 R2 = 0.999902 In the laboratory you measured RMSE, however here you will enter the R2 value displayed on the graph. SLOPE, (M-1) INTERCEPT R? Unrounded 4.26442 x 10³ 0.0202852 0.999902 Rounded 4.264 x 103 0.02029 0.9999 CALCULATED VALUE • The path length of the vial is 1.00 cm. Unrounded Rounded Molar absorption coefficient for Fe(SCN), (M-1 cm-1) 3 4
Transcribed Image Text:0.2 0.5×10-4 1x10-4 1.5x10-4 2x10-4 [Fe(SCN2+)]equ, (M) y = 4.26442 × 103 x + 0.0202852 R2 = 0.999902 In the laboratory you measured RMSE, however here you will enter the R2 value displayed on the graph. SLOPE, (M-1) INTERCEPT R? Unrounded 4.26442 x 10³ 0.0202852 0.999902 Rounded 4.264 x 103 0.02029 0.9999 CALCULATED VALUE • The path length of the vial is 1.00 cm. Unrounded Rounded Molar absorption coefficient for Fe(SCN), (M-1 cm-1) 3 4
PART 1. STANDARD SOLUTIONS AND DETERMINATION OF E EXPERIMENTAL DATA The initial concentrations of SCN after dilution were calculated as part of the Prelab Exercise. These will be equal to the equilibrium concentrations of Fe(SCN)². Write the correct answers in the chart below. FROM PRELAB EXPERIMENTAL DATA CALCULATED VALUES Sample 0.000300 M SCN,(mL) [Fe(SCN)**Jequ, (M) Absorbance 1 1.50 0.144898 3.00 x 10-5 2 3.50 0.322326 7.00 x 10-5 3 7.00 0.619060 1.40 x 10-4 4 10.00 0.871203 2.00 × 10-4
Transcribed Image Text:PART 1. STANDARD SOLUTIONS AND DETERMINATION OF E EXPERIMENTAL DATA The initial concentrations of SCN after dilution were calculated as part of the Prelab Exercise. These will be equal to the equilibrium concentrations of Fe(SCN)². Write the correct answers in the chart below. FROM PRELAB EXPERIMENTAL DATA CALCULATED VALUES Sample 0.000300 M SCN,(mL) [Fe(SCN)**Jequ, (M) Absorbance 1 1.50 0.144898 3.00 x 10-5 2 3.50 0.322326 7.00 x 10-5 3 7.00 0.619060 1.40 x 10-4 4 10.00 0.871203 2.00 × 10-4
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