(1) 2 H2 (g) + 02(g) → 2 H2O(g) AH = -484 kJ (2) N2 (g) + 3 H2(g) → 2 NH3 (g) ДН — —92 kJ (3) H20(1) → H20(g) AH +44 kJ (4) 2 N2(g) + 6 H20(1) → 4 NH3 (g) + 3 02(g) AH° = kJ

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 99QRT
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(1)
2 H2(g) + 02(g)
→ 2 H2O(g)
AH
-484 kJ
(2)
N2 (g) + 3 H2(g) → 2 NH3 (g)
ΔΗ
-92 kJ
%3D
(3)
H20(1) → H2O(g)
AH = +44 kJ
(4)
2 N2(g) + 6 H20(1) → 4 NH3(g) + 3 02 (g)
AH :
kJ
Transcribed Image Text:(1) 2 H2(g) + 02(g) → 2 H2O(g) AH -484 kJ (2) N2 (g) + 3 H2(g) → 2 NH3 (g) ΔΗ -92 kJ %3D (3) H20(1) → H2O(g) AH = +44 kJ (4) 2 N2(g) + 6 H20(1) → 4 NH3(g) + 3 02 (g) AH : kJ
Given the thermochemical equations for reactions (1),(2) and (3)
below, calculate the enthalpy change for reaction (4).
Transcribed Image Text:Given the thermochemical equations for reactions (1),(2) and (3) below, calculate the enthalpy change for reaction (4).
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