Use the 6-Step problem technique. definition,data ,theory,estimate ,solve,verify 1-A particle moving in two dimensions has a position vector (r) as a function of time (t) withcoordinates given byx(t) = t2 – 4t + 20y(t) = 3sin (2t)Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity(v) and the acceleration (a) at time t-3 s. (6-STEP METHOD)

SOlution: Given that two equation of x and y componetn of a vector x =t2-4t+20 y=3sin2t

1-A particle moving in two dimensions has a position vector (r) as a function of time (1) with coordinates given by x(t) = t? – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)

1-A particle moving in two dimensions has a position vector (r) as a function of time (1) with coordinates given by x(t) = t? – 4t + 20 y(t) = 3sin (2t) Where r is measured in millimetres and t is in seconds Determine the magnitude of the velocity (v) and the acceleration (a) at time t=3 s. (6-STEP METHOD)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 2P

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