1 AM Wed Nov 3 令@ 68%| T Chapter 7 Section 5 in your lecture textbook covers the calculations needed for this week's lab. They are very similar to calculations we covered previously. Complete the following before coming to lab. It will be GRADED! Given the balanced equation: HBr(ag) + NaOH(aq) → NaBr(aq) + H2OM and remembering that Molarity = moles/liter OR mmoles/mL (1) (a) Calculate the number of mmoles of HBr in 100.0 mL of 0.250 MHBR (0.250 MBr)(l00 ml) :25.0 mmoles of HBr (b) Calculate the number of mmoles of NaOH in 100.0 ml of 0.250 MNAOH (100 mL) (1.250 MNA PH) =e5.0 mmoles of NaOH) © When these two solutions are mixed the acid and base should neutralize one another exactly. This means that all of the acid and base are completely used up; either one could be considered a "limiting reactant". Starting with the mmoles of either the acid or base, calculate the number of mmoles of salt produced by the reaction. I mol Inol NaOH 25 x LoS mol Na OH = 25 mmol Na Br O Using the mmoles of salt produced and the total volume in ml of solution (from the mixing of the acid and base solutions), calculate the molarity of the salt solution produced by this reaction. : 25 x 10 mol - D. 025 nol Na Br 6.025 nol (NABr] - = (6.125 M 0.2 L (6) Concidor this examnle problem:
1 AM Wed Nov 3 令@ 68%| T Chapter 7 Section 5 in your lecture textbook covers the calculations needed for this week's lab. They are very similar to calculations we covered previously. Complete the following before coming to lab. It will be GRADED! Given the balanced equation: HBr(ag) + NaOH(aq) → NaBr(aq) + H2OM and remembering that Molarity = moles/liter OR mmoles/mL (1) (a) Calculate the number of mmoles of HBr in 100.0 mL of 0.250 MHBR (0.250 MBr)(l00 ml) :25.0 mmoles of HBr (b) Calculate the number of mmoles of NaOH in 100.0 ml of 0.250 MNAOH (100 mL) (1.250 MNA PH) =e5.0 mmoles of NaOH) © When these two solutions are mixed the acid and base should neutralize one another exactly. This means that all of the acid and base are completely used up; either one could be considered a "limiting reactant". Starting with the mmoles of either the acid or base, calculate the number of mmoles of salt produced by the reaction. I mol Inol NaOH 25 x LoS mol Na OH = 25 mmol Na Br O Using the mmoles of salt produced and the total volume in ml of solution (from the mixing of the acid and base solutions), calculate the molarity of the salt solution produced by this reaction. : 25 x 10 mol - D. 025 nol Na Br 6.025 nol (NABr] - = (6.125 M 0.2 L (6) Concidor this examnle problem:
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter6: Solutions And Colloids
Section: Chapter Questions
Problem 6.56P
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