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- It is known that acid content has a major effect on theflavor of vinegars, but most cheaper vinegars are diluted similarly to 5% acidity Wt./vol. % is equivalent to gsolute per 100mL solution (so 5% is equivalent to 5 g acid/100 mL solution). a.) First, calculate the approximate molar concentration of acetic acid in the 5% wt./vol vinegar. b.) Next, calculate the expected molarity of acetic acid in the solution upon dilution by a factor of 5. Thank you!A solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in a 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Additional information for 35-37 What if the solution has a total volume of 262ml? 1. Express the concentration of this solution in % by weight.a. 7.3%b. 4.4%c. 8.0%d. 7.8% 2. Express the concentration in molaritya. 0.10 Mb. 2.00 Mc. 0.76 Md. 0.93 M 3. Express the concentration in normalitya. 2.0 Nb. 1.5 Nc. 1.0 Nd. 0.76 N 4. Express the concentration in molalitya. 0.80 mb. 0.77 mc. 1.00 md. 1.50 m10) How can you prepare 500 ml of 0.1M HCI, if the percentage is 35%, and density = 1.18g/ml, M.mass=36.5 g/mol
- 0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. Answer must be in 4 decimal places.Q1/ prepare ( 0.3 M ) of HCl in 250 ml water, when you know Sp.Gr=1.18 and % = 36% . At.Wt / H=1 , Cl= 35.5Run 1 Run 2 Molarity of KMnO4 solution (M) from bottle 0.00101 0.00101 Initial reading of buret KMnO4 (mL) 0.62 11.35 Final reading of buret KMnO4 (mL) 11.33 21.70 Run 1 Run 2 Volume of KMnO4 solution (mL) Moles of MnO4- used for titration (mol) Moles of C2O42- in 100.0 mL of solution (mol) Molarity of C2O42- (M) Molarity of Cd2+ (M) Ksp of CdC2O4 Average Ksp of CdC2O4 Calculations: Moles of MnO4- used for titration of saturated solution CdC2O4 Moles of C2O42- in 100.0 mL of saturated solution of CdC2O4 Molarity of C2O42- in saturated solution of CdC2O4 Molarity of Cd2+ in saturated solution of CdC2O4 Solubility product, Ksp, of CdC2O4
- You measure 7.6mL of 1:1.92 bromine to acetic acid solution. How many moles and grams of bromine and acetic acid are in the 7.6mL?Dapsone tablets, labelled 50 mg has an average tablet weight of 0.6509 g. 2.0g of powdered tablets reacted (see reaction below) with 26.05 mL of 0.0506N sodium nitrite (NaNO2) solution. Determine the amount of Dapsone as a percentage of the Label Strength (or Label Claim). Report your answer to 1 decimal place. Given: Dapsone molar mass, 248.302 g/mol Dapsone structure Reaction: Sodium nitrite (NaNO2) reacts with hydrochloric acid (HCl) to generate nitrous acid (HNO2). NaNO2 + HCl ® HNO2 + NaCl Nitrous acid (HNO2) then reacts with each amino group on Dapsone, and an indicator indicates the endpoint. R-NH2 (full structure shown above) + HNO2 + HCl ® R-N2Cl + 2H2OAnswers should be in 4th decimal places An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (SG=1.114; MW = 62.07 g/mole) and water at 20oC. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol asa) Volume percentb) Mass percentc) Molarityd) Molalitye) Mole fraction
- Drug A dissociates into four ions to the extent of 70%. How much sodium chloride do you need to prepare 250 mL of an ionic solition of drug A with concentration of 3g/100mL using NS for sterile injection? MW of Drug A= 892.54 (assume final volume will be qs with sterile water for injection) a. 155.9 ml NaCl b. 62.37 mL NaCl c. 146.6 mL NaCl d. 218.33 mL NaClA 1.787 g sample containing some Fe2+ ion requires 31.50 ml of a 0.02188 M KMnO4solution to reach a pink endpoint. What is the percent by mass of Fe2+ in the sample?CALCULATE FINAL CONCETRATION INCLUDE UNITS AND 2 SIG FIGS A 43.5 mL sample of an 7.5 %(mm/vv) KBr solution is diluted with water so that the final volume is 215.5 mL.