1- Are the following changes in conditions likely to increase or decrease retention time?a. faster flow rateb. longer columnc. longer connector between column and detectord. higher analyte concentratione. higher temperaturef. larger sample sizeg. using a less polar column while doing a reverse-phase separationh. using a less polar mobile phase while doing a reverse-phase separation2- In what order will the following substances elute?• In reverse-phase liquid chromatography:a. butylamine, 2-butylene, ethylamine, ethyleneb. benzene, chlorophenol, phenol, trichlorophenol• In gas chromatography with a polar column:c. butanol, methanol, water• In gas chromatography with a nonpolar column:d. butanol, methanol, water• In ion chromatography:e. bromide, fluoride, sulfide

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1- Are the following changes in conditions likely to increase or decrease retention time? a. faster flow rate b. longer column c. longer connector between column and detector d. higher analyte concentration e. higher temperature f. larger sample size g. using a less polar column while doing a reverse-phase separation h. using a less polar mobile phase while doing a reverse-phase separation

1- Are the following changes in conditions likely to increase or decrease retention time? a. faster flow rate b. longer column c. longer connector between column and detector d. higher analyte concentration e. higher temperature f. larger sample size g. using a less polar column while doing a reverse-phase separation h. using a less polar mobile phase while doing a reverse-phase separation

Principles Of Pharmacology Med Assist

6th Edition

ISBN:9781337512442

Author:RICE

Publisher:RICE

Chapter8: Forms Of Drugs And How They Act

Section: Chapter Questions

Problem 30RQ

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A solution contains 1.0 g of ephedrine sulfate in a volume of 100 mL. What quantity of sodium chloride must be added to make the solution isotonic? E value for the drug is 0.23.
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This is what I did: to find change in concentration: 7.80e-18 - 4.50e-17 = -3.72e-17 Then applied diffusions law: (1.70e-9 x -3.72e-17 *5.20) / 1.00e-6 = -3.28848e-19 to convert to micrograms = -3.28848e-19 * 16g/mol * 1e6 mg/g = -5.26237e-12 micrograms.
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pls compute how to prepare the solutions1. 100.0 mL 0.0500 M stock Ca2+ solutiona. Weigh appropriate amount of pure CaCO3 (FW=100.09) to the nearest 0.1 mg into a 250 mL beaker. Add about 40.0 mL distilled water. Take note of the purity of CaCO3 used.b. Carefully and slowly add concentrated HCl to dissolve the CaCO3 solids while stirring and heating the solution in a hotplate. Do this until the CaCO3 solids are completely dissolved or until no more effervescence is observed.2. 100.0 mL 0.0500 M stock Ca2+ solutiona. Weigh appropriate amount of pure CaCO3 (FW=100.09) to the nearest 0.1 mg into a 250 mL beaker. Add about 40.0 mL distilled water. Take note of the purity of CaCO3 used.b. Carefully and slowly add concentrated HCl to dissolve the CaCO3 solids while stirring and heating the solution in a hotplate. Do this until the CaCO3 solids are completely dissolved or until no more effervescence is observed.NOTE: The stirring must be vigorous enough to dissolve the solids. It is advisable…
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