an acetylidean etheran alkyl bromideQUESTION 341) BH3 • THFCH3 - CH2- CH2 - CH = CH22) H2O2, OHpentan-1-olO pent-1-ynepentaneO butanoic acid and carbon dioxideO pentanoic acidQUESTION 35Which of the following molecules is responsible for this IR spectrum?Click Save and Submit to save and submit. Click Save All Answers to save all answers.O O OO O

Answered: 1) BH3 THF CH3 - CH2- CH2 - CH = CH,…

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1) BH3 THF CH3 - CH2- CH2 - CH = CH, %3D 2) H,O2, OH

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL4: Proton (1h) Nmr Spectroscopy

Section: Chapter Questions

Problem 3E: Here are proton NMR data for 1-bromopropane: Ha : triplet (2H) 3.32ppm; Hb : multiplet (2H)1.81ppm;...

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Assign the IR spectra given in Questions 1 - 3 to their corresponding structures from the ones below. The number in parentheses next to each possible answer corresponds to the structure's Chemical Abstracts Services (CAS) number. 1-bromobutane (109-65-9) 1-cyclopropylethan-1-one (765-43-5) 1-ethyl-3-methylbenzene (620-14-4) 1,2-dimethoxynenzene (91-16-7) 2,3-dimethylbutan-2-ol (594-60-5) 3-methylbutan-1-ol (123-51-3) 3,3-dimethylbutan-2-one (75-97-8) 4-benzylpiperidine (31252-42-3) 4-methoxybenzaldehyde (123-11-5) acetic anhydride (108-24-7) acetonitrile (75-05-8) acetyl chloride (75-36-5) anisole (100-66-3) benzaldehyde (100-52-7) benzoic acid (65-85-0) benzophenone (119-61-9) benzyl acetate (140-11-4) bromobenzene (108-86-1) cyclohex-2-en-1-one (930-68-7) cyclohexanone (108-94-1) cyclopent-2-en-1-one (930-30-3) diethylamine (109-89-7) dimethyl malonate (108-59-8) ethyl 2-cyanoacetate (105-56-6) ethynylbenzene (536-74-3) heptanoic acid…
For each set of spectral data below, draw the skeletal structure of the molecule that is consistent with the data. a. C5H12OMajor IR peaks: 3000 -2850 cm-11H NMR: 1.10 ppm (doublet); 3.60 ppm (septet), 3.8 ppm (quartet), 1.05 ppm (triplet) b. C3H6Br2Major IR peaks: 3000 -2850 cm-11H NMR: 2.4 ppm (quintet) and 3.5 ppm (triplet)
Analyze the IR for the molecular formula C8H8O3 (vanillin). List only the relevant absorbancies (it is not necessary to list anything in the fingerprint region), descriptions (s, m, w, br), and assignments (O-H, alkane C-H, etc.).
On spectra 1 are the mass, IR and 13 C and 1 H NMRspectra of an organic compound.1) a) From these spectra, determine the structure of the molecule.Remember to ignore the triad in the 13 C NMR spectrum at 77 ppm thatcomes from the NMR solvent. b) Draw the structure of the molecule and label each hydrogen with a letter(A, B, C...). Then fill in the peak assignment table below. hydrogen chemical shift integration splitting pattern couples to
I need help with questions please show on charts, please information Functional group- primary amine Derivatives - Benzamide unknown compound C3H9N 1: Label identifiable absorption above 1400 cm-1, sp2 carbon stretch foralkenes and aromatic, sp3 carbon-hydrogen stretch, sp2 carbon-hydrogenstretch, carbon hydrogen stretches of aldehyde, O-H stretch for alcohols, andcarboxylic acid, C=O stretches, N-H for amines.2- 1HNMR: Draw the structure neatly on the spectrum with each of the hydrogenclearly labelled. Identify which signal is associated with each type of H asmuch as possible.3- 13CNMR: Draw the structure neatly on the spectrum with each of the carbonclearly labelled. Identify which signal is associated with each type of carbonas much as possible
Here are proton NMR data for 1-bromopropane: Ha : triplet (2H) 3.32ppm; Hb : multiplet (2H)1.81ppm; Hc : triplet (3H) 0.93ppm. (Relative integrations shown in parentheses.) a. Through how many bonds can a hydrogen split another hydrogen? b. According to this splitting rule, does Ha split Hc ? c. Is your answer in part a) consistent with the multiplicity listed for peak clusters a and c? d. How many hydrogenssplit Hb ? e. Upon very close inspection of the proton NMR spectrum of 1-bromopropane, you wouldfind that peak cluster b has at least six peaks. Is this consistent with your answer in part d)? f. Speculate as to why any peak cluster with more than four peaks is listed simply as a"multiplet."
The hormone cortisone contains C, H, and O, and shows a molecular ion at M+=360.1937 by high-resolution mass spectrometry. What is the molecular formula of cortisone? (The degree of unsaturation for cortisone is 8.)
Following are infrared spectra of nonane and 1-hexanol. Assign each compound its correct spectrum.
For the following compound: C3H5BrO2 (Molecular Weight = 152) -Calculate the degrees of unsaturation -Use the IR and NMR to determine the structure for your compound -All 1H NMR peaks (number of signals, chemical shift, integration and splitting)-All 13C NMR peaks (number of signals and chemical shift)-All IR peaks that are important (no need to look into the fingerprint region!)-Your proposed structure of the compound (C3H5BrO2) and how it matches with the spectra (images attached)
N-propylbenzene, C6H5CH2CH3, contains C (sp3) -H and C (sp2) -H bonds. Its IR spectrum shows strong or medium absorptions at 3085, 3064, 3028, 2960, 2931 and 2873 cm ^ -1, as well as bands below 1600cm -1. Which statement is wrong? A.) Stretching of the C (sp3) -H bonds results in absorptions at lower wave numbers than the stretching of the C (sp2) -H bonds. B.) The absorptions at 2960, 2931 and 2873 cm ^ -1 are assigned to stretching of the C (sp3) -H bonds. C.) The absorptions at 3085, 3064 and 3028 cm ^ -1they are assigned to stretching of the C (sp2) -H bonds. D.) Each absorption can be assigned to the stretch mode of a particular bond in the propylbenzene molecule.
Ethers are not easily differentiated by their infrared spectra, but they tend to form predictable fragments in the mass spectrum. The following compounds give similar butdistinctive mass spectra.O Obutyl propyl ether butyl isopropyl etherBoth compounds give prominent peaks at m>z 116, 73, 57, and 43. But one compoundgives a distinctive strong peak at 87, and the other compound gives a strong peak at 101.Determine which compound gives the peak at 87 and which one gives the peak at 101.Propose fragmentations to account for the ions at m>z 116, 101, 87, and 73.
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