Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN: 9780618974122
Author: Andrei Straumanis
Publisher: Cengage Learning
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Chapter L4, Problem 3E

Here are proton NMR data for 1-bromopropane: H a : triplet (2H) 3.32ppm; H b : multiplet (2H)1.81ppm; H c : triplet (3H) 0.93ppm. (Relative integrations shown in parentheses.)
a. Through how many bonds can a hydrogen split another hydrogen?
b. According to this splitting rule, does H a split H c ?
c. Is your answer in part a) consistent with the multiplicity listed for peak clusters a and c?
d. How many hydrogenssplit H b ?
e. Upon very close inspection of the proton NMR spectrum of 1-bromopropane, you wouldfind that peak cluster b has at least six peaks. Is this consistent with your answer in part d)?
f. Speculate as to why any peak cluster with more than four peaks is listed simply as a"multiplet."

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NMR interpretation:Is this correct? My reasoning is the methyl is next to the green hydrogen so following the n+1 rule, would make the methyl a doublet (d). The hydrogen to the right of the carbonyl has no neighbors, so it's a singlet (s). And the green hydrogen is a quintet (m) since it has the 1 red hydrogen and the 3 black hydrogens as neighbors. Therefore, we should see a 3H, d 1-2.5 ppm; 1H m 4.5-6.5 ppm;  1H, d 4.5-6.5 ppm; and 1H, s 9-10ppm. If it's not correct, can you please explain how to predict the NMR patterns and integrations for this?Thank you!
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