(1) Mixing sodium carbonate and citric acid in a solution produces carbon dioxide that shows a s fizz. Given the balanced equation below, (on question 11) What amount in grams if citric acid (C6H8O7) should be added to 0.5 gram sodium carbonate (NaHCO3) to have a complete reaction? 3 NaHCO3 (aq) + C6H8O7 (aq) ---> 3 CO2 (g) + 3 H2O (I) + Na3C6HsO7 (aq) Molar Masses. 1 mole of NaHCO3 = 84.01 grams of NaHCO3 1 mole of C6H8O7 = 192.12 grams of C6H8O7 Ratio: 3 mole of NaHCO3 = 1 mole of C6H8O7

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Chapter9: Chemical Quantities
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Problem 47A
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(1) Mixing sodium carbonate and citric acid in a solution
produces carbon dioxide that shows a s fizz. Given the
balanced equation below,
(on question 11) What amount in grams if citric acid
(C6H8O7) should be added to 0.5 gram sodium carbonate
(NaHCO3) to have a complete reaction?
3 NaHCO3 (aq) + C6H8O7 (aq) ---> 3 CO2 (g) + 3 H2O (1) +
Na3C6H5O7 (aq)
Molar Masses.
mole of NaHCO3 = 84.01 grams of NaHCO3
1 mole of C6H8O7 = 192.12 grams of C6H807
Ratio:
3 mole of NaHCO3 = 1 mole of C6H8O7
Transcribed Image Text:(1) Mixing sodium carbonate and citric acid in a solution produces carbon dioxide that shows a s fizz. Given the balanced equation below, (on question 11) What amount in grams if citric acid (C6H8O7) should be added to 0.5 gram sodium carbonate (NaHCO3) to have a complete reaction? 3 NaHCO3 (aq) + C6H8O7 (aq) ---> 3 CO2 (g) + 3 H2O (1) + Na3C6H5O7 (aq) Molar Masses. mole of NaHCO3 = 84.01 grams of NaHCO3 1 mole of C6H8O7 = 192.12 grams of C6H807 Ratio: 3 mole of NaHCO3 = 1 mole of C6H8O7
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