1. A 4.00 mL sample of vinegar (active ingredient, acetic acid) was titrated with 0.1250M NAOH according to the following equation: NAC2H3O2 + HOH HC2H3O2 + NaOH 25.19 mL of base was needed to reach the end point. Calculate the molarity of the acetic acid. 2. Calculate the grams of acetic acid in one liter of the vinegar. 3. The 4.00 mL sample of vinegar had a mass of 4.056 g. Calculate the grams of vinegar in one liter. 4. Calculate the % acetic acid in the vinegar. % acetic acid g acetic acid g vinegar x 100 95
1. A 4.00 mL sample of vinegar (active ingredient, acetic acid) was titrated with 0.1250M NAOH according to the following equation: NAC2H3O2 + HOH HC2H3O2 + NaOH 25.19 mL of base was needed to reach the end point. Calculate the molarity of the acetic acid. 2. Calculate the grams of acetic acid in one liter of the vinegar. 3. The 4.00 mL sample of vinegar had a mass of 4.056 g. Calculate the grams of vinegar in one liter. 4. Calculate the % acetic acid in the vinegar. % acetic acid g acetic acid g vinegar x 100 95
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section: Chapter Questions
Problem 105GQ: Sodium bicarbonate and acetic acid react according to the equation NaHCO3(aq) + CH3CO2H(aq) ...
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