1. Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation. Al=27, S=32, H=D1, O=16 Al2(SO3)3 + 6 NaOH ------> 3 Na2SO3 + 2 Al(OH)3 a. Determine the limiting reactant if 20.0 g of Al2(SO3)3 reacts with 20.0 g of NaOH. b. Determine the number of moles and mass of Al(OH)3 c. Determine the number of moles and mass of Na2SO3

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1. Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following
equation.
Al=27, S=32, H=1, O=16
Al2(SO3)3 + 6 NaOH ------>
3 Na2SO3 + 2 Al(OH)3
a. Determine the limiting reactant if 20.0 g of Al2(SO3}3 reacts with 20.0 g of NaOH.
b. Determine the number of moles and mass of Al(OH)3
c. Determine the number of moles and mass of Na2SO3
Transcribed Image Text:1. Aluminum sulfite reacts with sodium hydroxide to form sodium sulfite and aluminum hydroxide according to the following equation. Al=27, S=32, H=1, O=16 Al2(SO3)3 + 6 NaOH ------> 3 Na2SO3 + 2 Al(OH)3 a. Determine the limiting reactant if 20.0 g of Al2(SO3}3 reacts with 20.0 g of NaOH. b. Determine the number of moles and mass of Al(OH)3 c. Determine the number of moles and mass of Na2SO3
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