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1).  Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M Ca(NO3)2 solution to 150.0mL. 2).  Determine the molarity of a solution formed by dissolving 468 mg of MgI2 in enough water to yield 50.0 mL of solution.3). What is the concentration of nitrate ions in a 0.125 M Mg(NO3)2 solution?4). How many moles of NaCl are required to make 250 mL of a 3.00 M solution?5). In order to prepare 60 g of 10% Sodium Carbonate solutions, how many grams of water and sodium carbonate is needed?6). Calculate how may grams of NaCl are needed to prepare a 250 mL of a 0.50 M solution?7). What volume of 12M Hydrochloric acid must be used to prepare 500 mL of a 6.0 M HCl solution?

Question

1).  Determine the concentration of a solution prepared by diluting 25.0 mL of a stock 0.188 M Ca(NO3)2 solution to 150.0mL. 

2).  Determine the molarity of a solution formed by dissolving 468 mg of MgI2 in enough water to yield 50.0 mL of solution.

3). What is the concentration of nitrate ions in a 0.125 M Mg(NO3)2 solution?

4). How many moles of NaCl are required to make 250 mL of a 3.00 M solution?

5). In order to prepare 60 g of 10% Sodium Carbonate solutions, how many grams of water and sodium carbonate is needed?

6). Calculate how may grams of NaCl are needed to prepare a 250 mL of a 0.50 M solution?

7). What volume of 12M Hydrochloric acid must be used to prepare 500 mL of a 6.0 M HCl solution?

check_circleAnswer
Step 1

Since, this is multiple questions we are answering first question.

Step 2

According to volumetric dilution law

V1N1=V2N2

Step 3

The concentration of a solution prepared can be calculated as

V1= initial volume (25mL)

N1=initial concentration (0.188M)

V2 = final volume (150mL)

N2 = V1 *N1...

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