1. Molecular Weight = 44; with 1 0 INFRARED SPECTRUM 0.8 0.6 0.4 0.2 2000 Wavenumber (cm-1) 3000 1000 2. Molecular Weight: 113; with 1 N (all other atoms are C and H) 0.8 0.4 2000 Wavenumber (cm-1) 3000 1000 Transmitance Transmitance

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter17: Applications Of Infrared Spectrometry
Section: Chapter Questions
Problem 17.4QAP
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Propose one possible structure for each of the following based on the spectra provided. Use the Rule of 13 to find a formula for any questions that only provide the Molecular Weight. Also to perform an IHD calculations.Fully
interpret the IR spectra to justify the structure you have chosen.

1. Molecular Weight = 44; with 10
INFRARED SPECTRUM
0.8
0.6
0.4
0.2
3000
2000
1000
Wavenumber (cm-1)
2. Molecular Weight: 113; with 1 N (all other atoms are C and H)
0.8
0.4
3000
1000
2000
Wavenumber (cm-1)
Transmitance
Transmitance
Transcribed Image Text:1. Molecular Weight = 44; with 10 INFRARED SPECTRUM 0.8 0.6 0.4 0.2 3000 2000 1000 Wavenumber (cm-1) 2. Molecular Weight: 113; with 1 N (all other atoms are C and H) 0.8 0.4 3000 1000 2000 Wavenumber (cm-1) Transmitance Transmitance
3. Given Formula: C11H200
70
50
40
30
008
WAVENUMBERS
0001
007
00+
009
0081
0007
2600 2400
0087
009E
3200 3000
008E
000
10
1727 cm³
N
09
08
06
13
9
00L
12
11
4.
5.5
4.5
SNOHJIW
3.5
2.5 2.6 2.7 2.8 2.9 3
Transcribed Image Text:3. Given Formula: C11H200 70 50 40 30 008 WAVENUMBERS 0001 007 00+ 009 0081 0007 2600 2400 0087 009E 3200 3000 008E 000 10 1727 cm³ N 09 08 06 13 9 00L 12 11 4. 5.5 4.5 SNOHJIW 3.5 2.5 2.6 2.7 2.8 2.9 3
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